The answer is bwhich is 196
Answer:
Step-by-step explanation:
x decreases w/o bound, so x becomes a very large -ve no.
f(x)=5^(x-1) becomes 5^(large -ve no.) which will be almost zero
x increases w/o bound, so x becomes a very large +ve no.
f(x)=5^(x-1) becomes 5^(large +ve no.) which will keep increasing w/o bound
if u provide wat the choices are from ur Q in comments, i will pick the right one 4 u
Ok! So, given a quadratic function<span>, </span>y<span> = ax</span>2<span> + bx + c, when "a" is positive, the </span>parabola <span>opens upward and the vertex is the minimum value. On the other hand, if "a" is negative, the graph opens downward and the vertex is the maximum value. Now, let's refer back to our original graph, </span>y<span> = </span><span>x2</span><span>, where "a" is 1.
Hope this helps.</span>
Answer:
C. x^2 -4
Step-by-step explanation:
What you do is subtract the functions as said by
(f-g)(x).
so:
f(x)-g(x)
(2x^2+3) - (x^2 -7)
2x^2 -x^2 +3 - 7= x^2 -4
Answer:
ammmm walang lumabas
Step-by-step explanation:
sorry talaga po sa susunod nalang
