Y=-4x²-4x+8
= -4(x²+x-2)
= 4(x+2)(x-1)
(-2,0),(1,0)
Important: If you're discussing squares, please express "the square of x" as x^2 (not as x2).
Please note that your y=x^2+3 is NOT a line. I will assume (probably incorrectly!) that you meant y=2x+3. The slope of this line is 2, so the slope of any line perpendicular to y=2x+3 is -1/2.
Now use the point-slope equation of a straight line:
y-8 = (-1/2)(x-1) (answer)
Http://mathsfirst.massey.ac.nz/Algebra/SystemsofLinEq/EMeth.htm this website explains it well
G=b-ca
Subtract b from both sides
G-b=-ca
Divide by -c
(G-b)/-c=a
I hope this Helps!
Answer:
10 minutes
Step-by-step explanation:
50 divided by 5= 10
