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Marrrta [24]
2 years ago
15

Select the correct answer.

Mathematics
1 answer:
dolphi86 [110]2 years ago
3 0

Check the picture below.

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If a fire is burning a building and it takes 2 hours to put it out using 2000 gal./min., what minimum diameter cylindrical tank
strojnjashka [21]

Answer:

The minimum diameter of the cylindrical tank needed to store the quantity needed to put out the fire is approximately 58.415 feet.

Step-by-step explanation:

A gallon equals 0.134 cubic feet. First, we determine the amount of water (Q), measured in cubic feet, needed to put out the fire under the assumption that water is consumed at constant rate:

Q = \dot Q \cdot \Delta t (1)

Where:

\dot Q - Volume rate, measured in feet per minute.

\Delta t - Time, measured in minutes.

If we know that \dot Q = 2000\,\frac{gal}{min} and \Delta t = 120\,min, then the amount of water is:

Q = \left(2000\,\frac{gal}{min} \right)\cdot (120\,min) \cdot \left(0.134\,\frac{ft^{3}}{gal} \right)

Q = 32160\,ft^{3}

And the diameter of the cylindrical tank based on the capacity found above is determined by volume formula for a cylinder:

Q = \frac{\pi}{4}\cdot D^{2}\cdot h (2)

Where:

D - Diameter, measured in feet.

h - Height, measured in feet.

If we know that Q = 32160\,ft^{3} and h = 12\,ft, then the minimum diameter is:

D^{2} = \frac{4\cdot Q}{\pi\cdot h}

D = 2\cdot \sqrt{\frac{Q}{\pi\cdot h} }

D = 2\cdot \sqrt{\frac{32160\,ft^{3}}{\pi\cdot (12\,ft)} }

D \approx 58.415\,ft

The minimum diameter of the cylindrical tank needed to store the quantity needed to put out the fire is approximately 58.415 feet.

8 0
3 years ago
1.73639 rounded to the nearest thousanth
Maurinko [17]
^ is in the thousadths place so look for the number before it, which is 3. 3 is less than 5 so 6 stays as is so it becomes 1.736
8 0
3 years ago
The difference between a number,x, and 4 is 9. find the number​
Elena-2011 [213]

let's set up an equation:

x-4=9

solve normally:

x=13

6 0
3 years ago
The area of a rectangle is 66 ft2, and the length of the rectangle is 1 ft more than twice the width. Find the dimensions of the
umka21 [38]
This is probably way overcomplicated but i cant remember how to do it
w = n
l = 2n+1
w*l = 66
n(2n+1) = 66
2n^2 + n =66
2n^2 + n - 66 = 0
using quadratic equation

n = 11/2

width = 11/2 = 5.5
length = 11 + 1 = 12
3 0
3 years ago
Roberta makes $9 an hour plus a 10.5% commission selling jewelry an hour shift in which she sells $880 worth of jewelry. How muc
timama [110]

Answer:

Roberta earns $164.4 on an 8 hr shift.

Step-by-step explanation:

In one hour  Roberta makes $9

So if she works for 8 hours she will be making

=> ( 9 X 8)$

=>72$

Also she earns a commission of 10.5% on selling a jewellery  worth $880

So 10.5% of 880 is

=> \frac{10.5}{100}\times 880

=>  0.105\times 880

=> 92.4

Hence  Roberta will be earning a total amount of

(72+ 92.4)

=>$164.4

3 0
3 years ago
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