EOLOOO
1 answer:
Answer:
λ = 2 m
f = 100 Hz
Explanation:
When struck in the middle an anti-node is formed at the center, So you can derive,
f = frequency of the fundamental mode in producing standing waves
l = resonating length
T = tension of the wire
m = linear density of the wire
(check the attachment)
By substituting,
f = 100 Hz
Wavelength is twice the vibrating length, its in the section standing waves and using that only the equation is derived.
Imagine what happens when two identical waves in opposite direction superimpose. There will be 3 nodes and two anti-nodes where the distance between two nodes is half the wavelength.
The same case happen here, the transverse sound wave traveling along the wire get reflected by a bridge and bounce back on itself where superposition takes place. So two nodes are at the bridges hence the twice of the distance between bridges is the wavelength of the sound wave.
You might be interested in
Answer:
Resultant displacement = 38.58 miles at an angle of 23.57° north of west.
Explanation:
Let north represent positive y direction and east represent positive x direction. Unit vector along x direction is represented by i and vector along unit vector along y direction is represented by j
Initial displacement = 17 miles north = 17 j miles
Final displacement = 24 miles at an angle of 40° west of north = 24 miles at an angle of 130° to positive x -axis
= (24 cos 130 i + 24 sin 130 j )
= (-15.43 i + 18.36 j ) miles
Total displacement = 17 j + (-15.43 i + 18.36 j) = -15.43 i + 35.36 j
Magnitude of displacement
Angle to positive x -axis = tan⁻¹(35.36/-15.43) = 113.57°
Resultant displacement = 38.58 miles at an angle of 23.57° west of north.