Answer:
methane + oxygen → carbon dioxide + water
Explanation:
methane + oxygen → carbon dioxide + water methane + oxygen → carbon dioxide + water methane + oxygen → carbon dioxide + water
Answer:
33.58%
Explanation:
Data obtained from the question include:
Mass of CuS = 9.56g
Mass of Cu = 6.35g
Mass of S = Mass of CuS — Mass and Cu
Mass of S = 9.56 — 6.35
Mass of S = 3.21g
The percentage by mass of sulphur in CuS is given by:
Mass of S/mass of CuS x 100
Percentage by mass of S = 3.21/9.56 x 100 = 33.58%
Answer:
Using the smallest coefficient the chemical equation is written as
3KOH(aq) + H3PO4(aq) → K3PO4(aq) + 3H2O(aq)
Explanation:
Neutralization reaction is a reaction in which acid and base reacts quantitatively to form salt and water.
Base = potassium hydroxide
acid = phosphoric acid.
KOH =potassium hydroxide
H3PO4 = Phosphoric acid
KOH(aq) + H3PO4(aq) → K3PO4(aq) + H2O(aq)
The number of atoms on both side (reactant and product) of the equation are not equal so, we need to balance it.
3KOH(aq) + H3PO4(aq) → K3PO4(aq) + 3H2O(aq)
The product are salt and water.
Salt = K3PO4
water = H2O
The equation is balanced on both sides .
The potassium atom is 3 on both sides , oxygen atom is 7 on both sides, hydrogen atom is 6 on both sides and phosphorus atom is 1 on both sides.
Answer:
The concentration of CH₃OH in equilibrium is [CH₃OH] = <em>2,8x10⁻¹ M</em>
Explanation:
For the equilibrium:
CO (g) + 2H₂(g) ⇄ CH₃OH(g) keq= 14,5
Thus:
14,5 =
In equilibrium, as [CO] is 0,15M and [H₂] is 0,36M:
14,5 =
Solving, the concentration of CH₃OH in equilibrium is:
<em>[CH₃OH] = 0,28M ≡ 2,8x10⁻¹ M</em>
I hope it helps!
Moles of ammonia is 2.4 moles
Molarity of solution after dilution is 2.4 M
Given:
volume of ammonia solution = 0.40 l
molarity of solution = 6.00 m
To Find:
moles of ammonia
Solution:
1 molar (M) solution will contain 1.0 GMW of a substance dissolved in water to make 1 liter of final solution
M = n / V
M is the molality of the solution that is to be calculated
n is the number of moles of the solute
V is the volume of solution given in terms of litres
n = M x V
= 6 x 0.4
= 2.4 moles
So moles of ammonia are 2.4 moles
molarity of the resulting solution after dilution
M = n/V
= 2.4/1
= 2.4 M
So Molarity after dilution will be 2.4 M
Learn more about Molarity here:
brainly.com/question/14469428
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