1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
marin [14]
2 years ago
15

Mitotic cyclins control the progression of S phase and mitosis. G1 phase and G2 phase. S phase and G2 phase. G2 phase and mitosi

s​
Chemistry
2 answers:
kotegsom [21]2 years ago
7 0

Answer:

The cell cycle involves different stages such as interphase, the Mitotic phase followed by cytokinesis.

The interphase involves G0 phase, G1 phase, Synthesis or S phase and G2 phase. The G stands for Gap phase.

The interpase involves the preparation of cellular contents, duplication of DNA. Then during mitosis karyokinesis occurs which is the division of duplicated chromosomes. And then through cytokinesis, the cytoplasmic contents also divides yielding two daughter cells.

Most of the cells normally enter into resting phase I.e., G0 phase and then start the process of cell division again. But some cells enter into G0 phase after the division and remain for longer duration. And this stage is called as quiescent or inactive stage. The mature heart muscle cell and nerve cell are the typical examples for this.

There are also some checkpoints in the cell cycle to check for any damage in the DNA from one phase to another phase and is mediated by Cyclins.

Apart from cyclins, the cyclin-dependent kinase also control the cell division.

These kinases are the enzymatic proteins which were activated by the binding of cyclins to it.

As the levels of different cyclins were different at each phase the amount of kinase activity is also regulated.

The kinases phosphorylates the target proteins which inturn helps in cell cycle such as break down of nuclear membrane during mitotic phase and promoting DNA replication in interphase.

These kinases were also down regulated by phosphorylating the sites where cyclin binds.

Therefore, cyclin dependent kinases can control cell cycle activities.

So, the correct answer is 'Cell cycle activities'

Umnica [9.8K]2 years ago
7 0

Answer:

The orderly series of events that lead to duplication of cell content followed by division of a cell into daughter cells is termed as the cell cycle. It consists of two phases, namely interphase and M phase. The M phase of cell cycle is marked by the division of nucleus and cytokinesis to produce daughter cells. Interphase is the period between two subsequent M phases and consists of three phases:

You might be interested in
What is the mass of a gold bar that is 7.379*10^-4 m^3 in volume?
NISA [10]
Mass to volume
M^3 --> cm^3
Cm^3 --> mL
Centi = 10*-2
7.379*10-4 / 1*10-2 = .07379

8 0
3 years ago
What happens to the electrons in an ionic bond?
Anton [14]

Answer:

In an ionic bonds, the metal loses electrons to become a positively charged cation, In which the nonmetal accepts those electrons to become a negatively charged anion.

Explanation:

3 0
3 years ago
Read 2 more answers
C2h6o how many moles of ethanol are present in a 10.0 g sample of ethanol
Dmitriy789 [7]
46 gram of ethanol ≡ 1 mole of ethanol
1 gram of ethanol ≡ 1/46 mole of ethanol
10 gram of ethanol ≡ 1*10/46 mole of ethanol
                               =0.217 mole of ethanol
5 0
3 years ago
Read 2 more answers
What is the name of the people who hid the Dead Seas Scrolls. When did they live at Qumran?
Shkiper50 [21]
It was named the Qumran seas scrolls.
3 0
2 years ago
i am begging anyone to help me with this! (all tutors i've asked said they can't solve it but i need someone to help me out) - i
9966 [12]

First, we need to calculate how much energy we will get from this combustion.

Assuming the combustion is complete, we have the octane reacting with O₂ to form only water and CO₂, so:

C_8H_{18}+O_2\to CO_2+H_2O

We need to balance the reaction. Carbon only appear on two parts, so, we can start by it:

C_8H_{18}+O_2\to8CO_2+H_2O

Now, we balance the hydrogen:

C_8H_{18}+O_2\to8CO_2+9H_2O

And in the end, the oxygen:

C_8H_{18}+\frac{25}{2}O_2\to8CO_2+9H_2O

We can multiply all coefficients by 2 to get integer ones:

2C_8H_{18}+25O_2\to16CO_2+18H_2O

Now, we need to use the enthalpies of formation to get the enthalpy of reaction of this reaction.

The enthalpy of reaction can be calculated by adding the enthalpies of formation of the products multiplied by their stoichiometric coefficients and substracting the sum of enthalpies of formation of the reactants multiplied by their stoichiometric coefficients.

For the reactants, we have (the enthalpy of formation of pure compounds is zero, which is the case for O₂):

\begin{gathered} \Delta H\mleft\lbrace reactants\mright\rbrace=2\cdot\Delta H\mleft\lbrace C_8H_{18}\mright\rbrace+25\cdot\Delta H\mleft\lbrace O_2\mright\rbrace \\ \Delta H\lbrace reactants\rbrace=2\cdot(-250.1kJ)+25\cdot0kJ \\ \Delta H\lbrace reactants\rbrace=-500.2kJ+0kJ \\ \Delta H\lbrace reactants\rbrace=-500.2kJ \end{gathered}

For the products, we have:

\begin{gathered} \Delta H_{}\mleft\lbrace product\mright\rbrace=16\cdot\Delta H\lbrace CO_2\rbrace+18\cdot\Delta H\lbrace H_2O\rbrace \\ \Delta H_{}\lbrace product\rbrace=16\cdot(-393.5kJ)+18\cdot(-285.5kJ) \\ \Delta H_{}\lbrace product\rbrace=-6296kJ-5139kJ \\ \Delta H_{}\lbrace product\rbrace=-11435kJ \end{gathered}

Now, we substract the rectants from the produtcs:

\begin{gathered} \Delta H_r=\Delta H_{}\lbrace product\rbrace-\Delta H\lbrace reactants\rbrace \\ \Delta H_r=-11435kJ-(-500.2kJ) \\ \Delta H_r=-10934.8kJ \end{gathered}

Now, this enthalpy of reaction is for 2 moles of C₈H₁₈, so for 1 mol of C₈H₁₈ we have half this value:

\Delta H_c=\frac{1}{2}\Delta H_r=\frac{1}{2}\cdot(-10934.8kJ)=-5467.4kJ

Now, we have 100 g of C₈H₁₈, and its molar weight is approximately 114.22852 g/mol, so the number of moles in 100 g of C₈H₁₈ is:

\begin{gathered} M_{C_8H_{18}}=\frac{m_{C_8H_{18}}}{n_{C_8H_{18}}} \\ n_{C_8H_{18}}=\frac{m_{C_8H_{18}}}{M_{C_8H_{18}}}=\frac{100g}{114.22852g/mol}\approx0.875438mol \end{gathered}

Since we have approximately 0.875438 mol, and 1 mol releases -5467.4kJ when combusted, we have:

Q=-5467.4kJ/mol\cdot0.875438mol\approx-4786.37kJ

Now, for the other part, we need to calculate how much heat it is necessary to melt a mass, <em>m</em>.

First, we have to heat the ice to 0 °C, so:

\begin{gathered} Q_1=m\cdot2.010J/g.\degree C\cdot(0-(-10))\degree C \\ Q_1=m\cdot2.010J/g\cdot10 \\ Q_1=m\cdot20.10J/g \end{gathered}

Then, we need to melt all this mass, so we use the latent heat now:

Q_2=n\cdot6.03kJ/mol

Converting mass to number of moles of water we have:

\begin{gathered} M=\frac{m}{n} \\ n=\frac{m}{M}=\frac{m}{18.01528g/mol} \end{gathered}

So:

Q_2=\frac{m}{18.01528g/mol}_{}\cdot6.03kJ/mol\approx m\cdot0.334716kJ/g

Adding them, we have a total heat of:

\begin{gathered} Q_T=m\cdot20.10J/g+m\cdot0.334716kJ/g \\ Q_T=m\cdot0.02010kJ/g+m\cdot0.334716kJ/g \\ Q_T=m\cdot0.354816kJ/g \end{gathered}

Since we have a heat of 4786.37 kJ form the combustion, we input that to get the mass (the negative sign is removed because it only means that the heat is released from the reaction, but now it is absorbed by the ice):

\begin{gathered} 4786.37kJ=m\cdot0.354816kJ/g \\ m=\frac{4786.37kJ}{0.354816kJ/g}\approx13489g\approx13.5\operatorname{kg} \end{gathered}

Since we have a total of 20kg of ice, we can clculate the percent using it:

P=\frac{13.5\operatorname{kg}}{20\operatorname{kg}}=0.675=67.5\%

5 0
10 months ago
Other questions:
  • This picture depicts secondary succession in a Forest ecosystem.
    7·1 answer
  • Which of the following methods estimates geologic events by comparing the objects to the layer of Earth they were discovered in?
    6·2 answers
  • Koi mera aake chus lo Aur heela bhi do​
    15·2 answers
  • An empty beaker weighs 32.4257 grams. A 10 ml pipet sample of an unknown liquid is
    5·1 answer
  • Calcium nitrate reacts with sodium phosphate to form sodium nitrate and calcium phosphate. Given 96.1 grams of calcium nitrate w
    10·1 answer
  • Nsity VVS
    13·1 answer
  • Which organisms are producers in a temperate coniferous forest? (Select all that apply.)
    11·2 answers
  • In what ways is the reaction between calcium and water different than the reactions between sodium and water, and potassium and
    7·1 answer
  • 2. Identify the limiting reactant when 4.68 g of iron reacts with 2.88 g of sulfur to produce Fes.
    13·1 answer
  • .Each of the three resonance structures of NO3– has how many lone pairs of electrons?
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!