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Finger [1]
3 years ago
10

Why does boron not always continue the period 2 pattern of reacting by losing electrons, as do beryllium and lithium?

Chemistry
2 answers:
gogolik [260]3 years ago
6 0
<span>Elements in Period 2 such as Barium and Beryllium can lose up to two electrons when they react, however Boron can lose up to three electrons when it reacts which causes it to break the pattern normally seen in Period 2.</span>
tensa zangetsu [6.8K]3 years ago
5 0
<h3><u>Answer;</u></h3>

because its a metalloid and the rest are all metals

<h3><u>Explanation;</u></h3>
  • Boron is a non metallic element and the only non-metal of the group 13 and a member of period 2 of the periodic table the elements. It is a metalloid as it posses both metallic and non-metallic characteristics.
  • Boron's reactivity is comparable to that of other elements in group 13 at very high temperatures. Unlike Boron, the metals in the group are good conductors under normal conditions. Boron is a good conductor only at high temperatures.
  • Beryllium and lithium  are metals and unlike boron they react by loosing electrons. Beryllium reacts by loosing two electrons while lithium reacts by loosing one valence electrons.
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3 years ago
If 650. grams of C6H12O6 (FW 180.16) reacts with 650. grams of O2 (FW 32.00) in cellular respiration: C6H12O6 6 O2 --&gt; 6 CO2
cestrela7 [59]

Answer:

O2 is limiting reactant

Explanation:

To find the limiting reactant we need to convert the mass of each reactant to the moles using the formula weight. And, as 1 mole of C6H12O6 reacts with 6 moles of O2, we can know wich reactant will be over first (Limiting reactant) as follows:

<em>Moles C6H12O6:</em>

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<em>Moles O2:</em>

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Now, for a complete reaction of 3.608 moles of C6H12O6 are required:

3.608 moles C6H12O6 * (6mol O2 / 1mol C6H12O6) = 21.65 moles O2

As there are just 20.31 moles of O2,

<h3>O2 is limiting reactant</h3>
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Answer:

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Explanation:

Increase is the answer hopes this helps you

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