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Finger [1]
3 years ago
10

Why does boron not always continue the period 2 pattern of reacting by losing electrons, as do beryllium and lithium?

Chemistry
2 answers:
gogolik [260]3 years ago
6 0
<span>Elements in Period 2 such as Barium and Beryllium can lose up to two electrons when they react, however Boron can lose up to three electrons when it reacts which causes it to break the pattern normally seen in Period 2.</span>
tensa zangetsu [6.8K]3 years ago
5 0
<h3><u>Answer;</u></h3>

because its a metalloid and the rest are all metals

<h3><u>Explanation;</u></h3>
  • Boron is a non metallic element and the only non-metal of the group 13 and a member of period 2 of the periodic table the elements. It is a metalloid as it posses both metallic and non-metallic characteristics.
  • Boron's reactivity is comparable to that of other elements in group 13 at very high temperatures. Unlike Boron, the metals in the group are good conductors under normal conditions. Boron is a good conductor only at high temperatures.
  • Beryllium and lithium  are metals and unlike boron they react by loosing electrons. Beryllium reacts by loosing two electrons while lithium reacts by loosing one valence electrons.
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Which of the following is a homogeneous mixture ?A.pizza B.oxygen <br> C.tea<br> D .pure water
Lubov Fominskaja [6]

I think it would be d bc water is everywhere

7 0
3 years ago
How many moles of ba(oh)2 are present in 275 ml of 0.200 m ba(oh)2?
DENIUS [597]
You have to put your attention to the unit of concentration. It is expressed in terms of molarity, which is represented in M. It is the number of moles solute per liter solution. So, you simply have to multiply the molarity with the volume in liters.

Volume = 275 mL * 1 L/1000 mL = 0.275 L
<em>Moles Ba(OH)₂ = (0.200 M)(0.275 L) = 0.055 mol</em>
6 0
4 years ago
5. How many mm are equal to 4.75 x 10-2 m?
liq [111]

Answer:

47.5 mm are equal to 4.75 × 10⁻² m.

Explanation:

Meter and millimeter both are units of length. Millimeter is smaller unit while meter is larger unit. The one meter consist of thousand millimeter or we can say that one thousand millimeters are equal to one meter. In order to convert the meter value into millimeter we have to multiply the values with thousand.

we know that one meter is equal to 1000 millimeter.

1 m = 1000 mm

4.75 × 10⁻² × 1000 = 47.5 mm

47.5 mm are equal to 4.75 × 10⁻² m.

6 0
3 years ago
Which of these solutions are basic at 25 °C? Solution A: [OH−]=3.13×10−7 M Solution C: [H3O+]=0.000747 M Solution B: [H3O+
solong [7]

Answer:

Are basic:

[OH⁻] = 3.13x10⁻⁷M and [H₃O⁺] = 9.55x10⁻⁹M

Explanation:

A solution is basic when pH = - log [H₃O⁺] is higher than 7.

It is possible to convert [OH⁻] to [H₃O⁺] using:

[H₃O⁺] = 1x10⁻¹⁴ / [OH⁻]

a. [OH⁻] = 3.13x10⁻⁷M

[H₃O⁺] = 1x10⁻¹⁴ / [3.13x10⁻⁷M]

[H₃O⁺] = 3.19x10⁻⁸M

pH = - log [H₃O⁺] = 7.50

[OH⁻] = 3.13x10⁻⁷M is basic

b. pH = -log [H₃O⁺] = - log 0.000747M = 3.13.

This solution is not basic

c. [H₃O⁺] = 9.55x10⁻⁹M

pH = 8.02

This solution is also basic.

8 0
3 years ago
What is the net ionic equation of the reaction of FeCl2 with NaOH? Express you answer as a chemical equation including phases.
Lilit [14]

Answer:

Fe²⁺(aq) + 2OH⁻(aq) → Fe(OH)₂(s)

Explanation:

To determine the reaction, we define the reactants:

FeCl₂, NaOH

We dissociate them:

FeCl₂(aq) → Fe²⁺(aq) + 2Cl⁻ (aq)

NaOH (aq) → Na⁺ (aq) + OH⁻(aq)

Salts from chloride are soluble, except for Ag⁺, Pb²⁺, Hg₂²⁺, Cu⁺

The OH⁻ and the Fe²⁺ bonds to make a precipitate.

So, the molecular complete equation is:

FeCl₂(aq) +  2NaOH(aq) →  Fe(OH)₂(s) ↓ + 2NaCl(aq)

When we dissociate the elements, we get the net ionic equation but as we produced an state's change, the compound stays the same.

We cancel the spectators ions (the ones, that are repeated)

Fe²⁺(aq) + 2Cl⁻ (aq) + 2Na⁺ (aq) + 2OH⁻(aq) → Fe(OH)₂(s) + 2Na⁺(aq) + 2Cl⁻(aq)

Fe²⁺(aq) + 2OH⁻(aq) → Fe(OH)₂(s)

5 0
3 years ago
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