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Finger [1]
3 years ago
10

Why does boron not always continue the period 2 pattern of reacting by losing electrons, as do beryllium and lithium?

Chemistry
2 answers:
gogolik [260]3 years ago
6 0
<span>Elements in Period 2 such as Barium and Beryllium can lose up to two electrons when they react, however Boron can lose up to three electrons when it reacts which causes it to break the pattern normally seen in Period 2.</span>
tensa zangetsu [6.8K]3 years ago
5 0
<h3><u>Answer;</u></h3>

because its a metalloid and the rest are all metals

<h3><u>Explanation;</u></h3>
  • Boron is a non metallic element and the only non-metal of the group 13 and a member of period 2 of the periodic table the elements. It is a metalloid as it posses both metallic and non-metallic characteristics.
  • Boron's reactivity is comparable to that of other elements in group 13 at very high temperatures. Unlike Boron, the metals in the group are good conductors under normal conditions. Boron is a good conductor only at high temperatures.
  • Beryllium and lithium  are metals and unlike boron they react by loosing electrons. Beryllium reacts by loosing two electrons while lithium reacts by loosing one valence electrons.
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Really need help on this thing plz someone... help number 2 and 3:(
olasank [31]

Answer:

I don't have one sorry

Explanation:

it's because I can't see the question I don't know it I'm sorry dude

8 0
2 years ago
E. H2CrO4 + Sr(OH)2 →
katrin2010 [14]

Answer:

The answer to your question is SrCrO₄ +  H₂O

Explanation:

Data

  H₂CrO₄  +  Sr(OH)₂  ⇒  

We can notice that this is a Redox reaction or neutralization reaction because the reactants are an acid (H₂CrO₄) and a base (Sr(OH)₂). These reactions are also called double displacement reactions.

In these kind of reactions the products are always a binary or ternary salt and water.

Then, for this reaction,

           H₂CrO₄  +  Sr(OH)₂  ⇒   SrCrO₄ +  H₂O

6 0
3 years ago
Read 2 more answers
Iron fluoride (FeF2) dissociates according to the following equation:
melomori [17]

Answer:

S = 0.788 g/L

Explanation:

The solubility product (Kps) is an equilibrium solubization constant, which can be calculated by the equation:

Kps = \frac{[product]^x}{[reagent]^y}

Where x and y are the stoichiometric coefficients of the product and the reagent, respectively. Because of the aggregation form, the concentration of solids is always equal to 1 for use in this equation.

Analyzing the equation, we see that for 1 mol of Fe^{+2} is necessary 2 mols of F^-, so if we call "x" the molar concentration of Fe^2, for F^- we will have 2x, so:

Kps = [Fe^{+2}].[F^-]^2\\\\2.36x10^{-6} = x(2x)^2\\\\2.36x10^{-6} = 4x^3\\\\x^3 = 5.9x10^{-7}\\\\x = \sqrt[3]{5.9x10^{-7}} \\\\x = 8.4x10^{-3} mol/L

So, to calculate the solubility (S) of FeF2, which is in g/L, we multiply this concentration by the molar mass of FeF2, which is:

Fe = 55.8 g/mol

F = 19 g/mol

FeF2 = Fe + 2xF = 55.8 + 2x19 = 93.8 g/mol

So,

[tex]S = 8.4x10^{-3}x93.8

S = 0.788 g/L

4 0
3 years ago
Ns
Brut [27]

Answer:

Ca(OH)₂ + H₂SO₄     →     CaSO₄ + H₂O

Explanation:

Chemical equation:

Ca(OH)₂ + H₂SO₄     →     CaSO₄ + H₂O

Balanced chemical equation:

Ca(OH)₂ + H₂SO₄     →     CaSO₄ + 2H₂O

The given reaction is double displacement reaction in which anion and cation of both reactant exchanged with each other. Calcium hydroxide react with sulfuric acid and form calcium sulfate and water.

Double replacement:

It is the reaction in which two compound exchange their ions and form new compounds.

AB + CD → AD +CB

6 0
3 years ago
Will chlorine gas effuse more quickly than ammonia gas
beks73 [17]
This statement is false due to the fact that the ammonia gas has the lower molar mass.
6 0
3 years ago
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