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erik [133]
3 years ago
12

Math does anyone know the answer?

Mathematics
1 answer:
Nastasia [14]3 years ago
6 0

Answer: m<3 is 36 degrees.

Step-by-step explanation:

7x=3x+9+3x

7x=6x+9

-6x  -6x

x=9

m<3=3(9)+9

m<3=27+9

m<3=36

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It’s 2500 because I solved it I just need to do 25*100 so I hope it’s right
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A triangle is placed in a semicircle with a radius of 7mm , as shown below. Find the area of the shaded region. Use the value 3.
timurjin [86]
We either need to see a picture of this and/or get more information about the measurements of the triangle. In general, the area outside of the triangle will be the area of the semi-circle minus the area of the triangle itself, or: 1/2*49*3.14 - 1/2 b*h of the triangle. That first part, which is the area of the semi-circle, works out to 76.93 So based on the info we have, it becomes 76.93 - 1/2*b*h of the triangle = area outside of triangle. 
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4 years ago
Evelyn is mixing light blue paint. The ratio of blue to white paint is 3:1. If Evelyn uses 6 parts blue paint. How much white pa
MAVERICK [17]

Answer:

2 parts white paint

Step-by-step explanation:

Blue : white

3      :    1

We use 6 parts blue

3 *2 =6

So multiply each part by 2

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3*2   :    1*2

6       : 2

She uses 2 parts white paint

3 0
3 years ago
EASY MATH (no links or get reported)
katovenus [111]

Answer:

Find the Roots (Zeros) f(x)=x^3-6x^2+13x-20. f(x)=x3−6x2+13x−20 f ( x ) = x 3 - 6 x 2 + 13 x - 20. Set x3−6x2+13x−20 x 3 - 6 x 2 + 13 x - 20 equal to 0 0 .

Step-by-step explanation:

hope this helps

4 0
3 years ago
If T: (x, y) → (x + 6, y + 4), then T-1: (x,y) → _____.
alexgriva [62]

T is a linear transformation from R²→R² with basis {(1,0),(0,1)}
T: (x,y)→(x+6,y+4)

A function from one vector space to another that preserves the underlying (linear) structure of each vector space is called a linear transformation.

Then the vector (1,0) goes to (1+6,4)=(7,4)=7(1,0)+4(0,1)

and the vector (0,1) goes to (6,1+4)=(6,5)=6(1,0)+5(0,1)

So, the matrix of the transformation is

\left[\begin{array}{ccc}7&6\\4&5\end{array}\right]

The inverse of the matrix is

\left[\begin{array}{ccc}\frac{5}{11}&\frac{-6}{11}\\ \\\frac{-4}{11}&\frac{7}{11}\end{array}\right]

So, the Inverse Transformation is given by

T^{-1}(x,y)=\left[\begin{array}{ccc}\frac{5}{11}&\frac{-6}{11}\\ \\\frac{-4}{11}&\frac{7}{11}\end{array}\right]\left[\begin{array}{ccc}x\\y\end{array}\right] =(\frac{5x-6y}{11}, \frac{-4x+7y}{11})

So, no option is correct. And the answer is

T^{-1}(x,y)=(\frac{5x-6y}{11}, \frac{-4x+7y}{11})

Learn more about linear transformations here-

brainly.com/question/13005179

#SPJ10

5 0
2 years ago
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