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crimeas [40]
4 years ago
13

EVALUATE 8+3⋅4 OVER 2 THE ANSWERS ARE 8 10 16 22

Mathematics
1 answer:
slavikrds [6]4 years ago
7 0
PEMDAS so you do 3*4 which equals 12, then you add 8=20 20/2=10

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The two-way table shows the number of students in class who play basketball and/or football,
allochka39001 [22]

total that play football = 40


 30 of them play basket ball


the missing number is 40 - 30 = 10

5 0
4 years ago
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You want to buy a DVD that costs $19.95. Estimate the total cost if the sales tax rate is 8%.
meriva

Answer:

$1.60

Step-by-step explanation:

first you take 19.95 times .08 and you get 1.596 you round up to get 1.6

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Step-by-step explanation:

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Analyze the diagram below and complete the instructions that follow.
lora16 [44]

Answer:

\displaystyle y=2\sqrt{6}

\displaystyle x=2\sqrt{2}

Step-by-step explanation:

<u>Trigonometric Ratios </u>

The ratios of the sides of a right triangle are called trigonometric ratios.

The longest side of the right triangle is called the hypotenuse and the other two sides are the legs.

Selecting any of the acute angles as a reference, it has an adjacent side and an opposite side. The trigonometric ratios are defined upon those sides.

The image provided shows a right triangle whose hypotenuse is given. We are required to find the value of both legs.

Let's pick the angle of 30°. Its adjacent side is y. We can use the cosine ration, which is defined as follows:

\displaystyle \cos 30^\circ=\frac{\text{adjacent leg}}{\text{hypotenuse}}

\displaystyle \cos 30^\circ=\frac{y}{4\sqrt{2}}

Solving for y:

y=4\sqrt{2}\cos 30^\circ

Since:

\cos 30^\circ=\frac{\sqrt{3}}{2}

\displaystyle y=4\sqrt{2}\frac{\sqrt{3}}{2}

Simplifying:

\displaystyle y=2\sqrt{6}

Now we use the sine ratio:

\displaystyle \sin 30^\circ=\frac{\text{opposite leg}}{\text{hypotenuse}}

\displaystyle \sin 30^\circ=\frac{x}{4\sqrt{2}}

Solving for x:

x=4\sqrt{2}\sin 30^\circ

Since:

\sin 30^\circ=\frac{1}{2}:

\displaystyle x=4\sqrt{2}\frac{1}{2}

Simplifying:

\displaystyle x=2\sqrt{2}

The choices are not clear, but it seems like the correct answer is C.

\boxed{\displaystyle y=2\sqrt{6}}

\boxed{\displaystyle x=2\sqrt{2}}

6 0
3 years ago
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