Dado um triângulo ABC, marca-se um ponto D no lado AB. Mostre que CD é menor do que o comprimento de um dos lados AC ou BC.
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I've drawn a triangle to represent the journey (see attached.
The angle from Home to Victim to Hospital is:
a =
Using the cos rule, we can solve for the length x:
Using the cos rule, we can solve for angle b:
So the bearing the helicopter has to travel is:
270 - 76.1 = <u>193.9 degrees (1 dp)</u>
And the distance it travels is <u>31.2 km (1 dp)</u>
The angle from Home to Victim to Hospital is:
a =
Using the cos rule, we can solve for the length x:
Using the cos rule, we can solve for angle b:
So the bearing the helicopter has to travel is:
270 - 76.1 = <u>193.9 degrees (1 dp)</u>
And the distance it travels is <u>31.2 km (1 dp)</u>