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3 years ago

If the volume of the polyhedron is 147π in^3, the value of x is ___ cm.

Mathematics

1 answer:

hram777 [196]3 years ago

4 0

Answer:

x = 6.44 cm

Step-by-step explanation:

Given that,

Volume, V = 147π in³

Height, h = 9 cm = 3.54 in

We need to find the value of x. The formula of this polyhedron is given by :

$V=\pi r^2 h\\\\r=\sqrt{\dfrac{V}{\pi h}} \\\\r=\sqrt{\dfrac{147\pi }{\pi \times 3.54}} \\\\r=6.44\ in$

r = 16.35 cm

So, the value of x is equal to 6.44 cm.

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CAN YOU GUYS HELP PLEASE, I HAVE A LIMIT ON THIS!!!!

lorasvet [3.4K]

Answer:

the 2nd choice

Step-by-step explanation:

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4 0

2 years ago

Read 2 more answers

The average THC content of marijuana sold on the street is 9.3%. Suppose the THC content is normally distributed with standard d

velikii [3]

Answer:

a) $X \sim N(9.3,1)$

b) $P(X>9.2)=P(\frac{X-\mu}{\sigma}>\frac{9.2-\mu}{\sigma})=P(Z>\frac{9.2-9.3}{1})=1-P(Z$

c) The value of height that separates the bottom 75% of data from the top 25% is 9.9745.

Step-by-step explanation:

1) Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

2) Part a

Let X the random variable that represent the heights of a population, and for this case we know the distribution for X is given by:

$X \sim N(9.3,1)$

Where $\mu=9.3$ and $\sigma=1$

3) Part b

We are interested on this probability

$P(X>9.2)$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(X>9.2)=P(\frac{X-\mu}{\sigma}>\frac{9.2-\mu}{\sigma})=P(Z>\frac{9.2-9.3}{1})=1-P(Z$

4) Part c

For this part we want to find a value a, such that we satisfy this condition:

$P(X>a)=0.25$ (a)

$P(X$ (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.

As we can see on the figure attached the z value that satisfy the condition with 0.75 of the area on the left and 0.25 of the area on the right it's z=0.6745. On this case P(Z<0.6745)=0.75 and P(z>0.6745)=0.25

If we use condition (b) from previous we have this:

$P(X$

$P(Z$

But we know which value of z satisfy the previous equation so then we can do this:

$z=0.6745$

And if we solve for a we got

$a=9.3 +1*0.6745=9.9745$

So the value of height that separates the bottom 75% of data from the top 25% is 9.9745.

8 0

3 years ago

Y varies directly as x if y is 2 when x is 8 then the constant of variation is 1/4

sp2606 [1]

Answer:

a. True.

Step-by-step explanation:

y = kx

y = 2 when x = 8 gives:

2 = 8 * k

k = 2/8 = 1/4.

6 0

3 years ago

Determine the measure of each segment then indicate whether the statements are true or false

kupik [55]

Answer:

$d_{AB}\ne d_{JK}$

$d_{AB}\ne \:d_{GH}$

$d_{GH}\ne \:d_{JK}$

Therefore,

Option (A) is false

Option (B) is false

Option (C) is false

Step-by-step explanation:

Considering the graph

Given the vertices of the segment AB

A(-4, 4)

B(2, 5)

Finding the length of AB using the formula

$d_{AB}\:=\:\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$

$=\sqrt{\left(2-\left(-4\right)\right)^2+\left(5-4\right)^2}$

$=\sqrt{\left(2+4\right)^2+\left(5-4\right)^2}$

$=\sqrt{6^2+1}$

$=\sqrt{36+1}$

$=\sqrt{37}$

$d_{AB}\:=\sqrt{37}$

$d_{AB}=6.08$ units

Given the vertices of the segment JK

J(2, 2)

K(7, 2)

From the graph, it is clear that the length of JK = 5 units

$d_{JK}=5$ units

Given the vertices of the segment GH

G(-5, -2)

H(-2, -2)

Finding the length of GH using the formula

$d_{GH}\:=\:\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$

$=\sqrt{\left(-2-\left(-5\right)\right)^2+\left(-2-\left(-2\right)\right)^2}$

$=\sqrt{\left(5-2\right)^2+\left(2-2\right)^2}$

$=\sqrt{3^2+0}$

$=\sqrt{3^2}$

$\mathrm{Apply\:radical\:rule\:}\sqrt[n]{a^n}=a,\:\quad \mathrm{\:assuming\:}a\ge 0$

$d_{GH}\:=\:3$ units

Thus, from the calculations, it is clear that:

$d_{AB}=6.08$

$d_{JK}=5$

$d_{GH}\:=\:3$

Thus,

$d_{AB}\ne d_{JK}$

$d_{AB}\ne \:d_{GH}$

$d_{GH}\ne \:d_{JK}$

Therefore,

Option (A) is false

Option (B) is false

Option (C) is false

8 0

3 years ago

The table shows the height of 5 students in inches what is the mean absolute deviation for these numbers

german

Answer:

Step-by-step explanation:

To find the mean absolute deviation (MAD), first find the mean (or average).

μ = (59 + 71 + 68 + 75 + 67) / 5

μ = 68

Next, subtract the mean from each value and take the absolute value.

|59 − 68| = 9

|71 − 68| = 3

|68 − 68| = 0

|75 − 68| = 7

|67 − 68| = 1

Sum the results and divide by the number of students.

MAD = (9 + 3 + 0 + 7 + 1) / 5

MAD = 4

3 0

3 years ago