Answer:
0.765.
Step-by-step explanation:
In the simplest way, then, it would be the quotient between both net income, how do we want to know the ratio of the first 6 months of the year to the last 6 months, then we would divide the net income of the first 6 months by the net income of the last 6 months 6 months, like this:
$ 76,500.00 / $ 100.00.00 = 0.765
Therefore the ratio is 0.765
Hi There!
Alright- Lets do this!
#1: PEMDAS
P
E
M/D
A/S
(8 + 7) - (8 x 9) + 800 + (50 + 90) + (8 x 9) - (11 - 25)
P - Parentheses
15 - 72 + 800 + 140 + 72 - (-14)
E - Exponents
There are none
M- multiply
there are none
D-Divide
There are none
Add
<span>15 - 72 + 800 + 140 + 72 - (-14)
</span>15 - (72+800+140+72 + 14)
*Note: subtracting a negative number is the same as adding it!*
15-1098
S - subtract
Answer: -1083
Hope this helped!
Answer:
448
Step-by-step explanation:
Parallelograms = 2x14x10=280
Triangles = 3x1/2x8x14=168
280+168=448
You are asked to do this problem by graphing, which would be hard to do over the Internet unless you can do your drawing on paper and share the resulting image by uploading it to Brainly.
If this were homework or a test, you'd get full credit only if you follow the directions given.
If <span>The points(0,2) and (4,-10) lie on the same line, their slope is m = (2+10)/(-4), or m =-3. Thus, the equation of this line is y-2 = -3x, or y = -3x + 2.
If </span><span>points (-5,-3) and (2,11) lie on another line, the slope of this line is:
m = 14/7 = 2. Thus, the equation of the line is y-11 = 2(x-2), or y = 11+2x -4, or y = 2x + 7.
Where do the 2 lines intersect? Set the 2 equations equal to one another and solve for x:
</span>y = -3x + 2 = y = 2x + 7. Then 5x = 5, and x=1.
Subst. 1 for x in y = 2x + 7, we get y = 2(1) + 7 = 9.
That results in the point of intersection (2,9).
Doing this problem by graphing, on a calculator, produces a different result: (-1,5), which matches D.
I'd suggest you find and graph both lines yourself to verify this. If you want, see whether you can find the mistake in my calculations.