<em>AC bisects ∠BAD, => ∠BAC=∠CAD ..... (1)</em>
<em>thus in ΔABC and ΔADC, ∠ABC=∠ADC (given), </em>
<em> ∠BAC=∠CAD [from (1)],</em>
<em>AC (opposite side side of ∠ABC) = AC (opposite side side of ∠ADC), the common side between ΔABC and ΔADC</em>
<em>Hence, by AAS axiom, ΔABC ≅ ΔADC,</em>
<em>Therefore, BC (opposite side side of ∠BAC) = DC (opposite side side of ∠CAD), since (1)</em>
<em />
Hence, BC=DC proved.
Answer:
2 miles.
Step-by-step explanation: Because 528 times 20 is 10560 then divide by 5280 equaling 2 miles.
30: x
60: xsqrt3
90: 2x (hypotenuse)
9514 1404 393
Answer:
12.0 cm
Step-by-step explanation:
Use the formula for the volume of a cylinder. Fill in the given values and solve for the height.
V = πr^2h
1846 cm^3 = π(7 cm)^2·h
h = 1846/(49π) cm ≈ 12.0 cm . . . . . . divide by the coefficient of h
The height of the can is about 12.0 cm.
Answer:
Explicit formula is
.
Recursive formula is 
Step-by-step explanation:
Step 1
In this step we first find the explicit formula for the height of the ball.To find the explicit formula we use the fact that the bounces form a geometric sequence. A geometric sequence has the general formula ,
In this case the first term
, the common ratio
since the ball bounces back to 0.85 of it's previous height.
We can write the explicit formula as,

Step 2
In this step we find the recursive formula for the height of the ball after each bounce. Since the ball bounces to 0.85 percent of it's previous height, we know that to get the next term in the sequence, we have to multiply the previous term by the common ratio. The general fomula for a geometric sequene is 
With the parameters given in this problem, we write the general term of the sequence as ,
