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Kipish [7]
3 years ago
14

A body was found at 6 a.m. in a warehouse where the temperature was 50°F. The medical examiner found the temperature of the body

to be 66°F. What was the approximate time of death? Use Newton's law of cooling, with k = 0.1947.
T(t)=T[A] + (T[O]-T[A])e^-kt
Mathematics
2 answers:
ankoles [38]3 years ago
6 0
<span>It was at Midnight (12 a.m.) </span>
fenix001 [56]3 years ago
4 0

Answer: 12 a.m.


Step-by-step explanation:


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A college infirmary conducted an experiment to determine the degree of relief provided by three cough remedies. Each cough remed
KiRa [710]

Answer:

p_v = P(\chi^2_{4,0.05} >3.81)=0.43233

Since the p values is higher than the significance level we FAIL to reject the null hypothesis at 5% of significance, and we can conclude that we don't have significant differences between the 3 remedies analyzed. So we can say that the 3 remedies ar approximately equally effective.

Step-by-step explanation:

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

Assume the following dataset:

                               NyQuil          Robitussin       Triaminic     Total

No relief                    11                     13                      9               33

Some relief               32                   28                     27              87

Total relief                7                       9                      14               30

Total                         50                    50                    50              150

We need to conduct a chi square test in order to check the following hypothesis:

H0: There is no difference in the three remedies

H1: There is a difference in the three remedies

The level os significance assumed for this case is \alpha=0.05

The statistic to check the hypothesis is given by:

\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}

The table given represent the observed values, we just need to calculate the expected values with the following formula E_i = \frac{total col * total row}{grand total}

And the calculations are given by:

E_{1} =\frac{50*33}{150}=11

E_{2} =\frac{50*33}{150}=11

E_{3} =\frac{50*33}{150}=11

E_{4} =\frac{50*87}{150}=29

E_{5} =\frac{50*87}{150}=29

E_{6} =\frac{50*87}{150}=29

E_{7} =\frac{50*30}{150}=10

E_{8} =\frac{50*30}{150}=10

E_{9} =\frac{50*30}{150}=10

And the expected values are given by:

                               NyQuil          Robitussin       Triaminic     Total

No relief                    11                     11                       11               33

Some relief               29                   29                     29              87

Total relief                10                     10                     10               30

Total                         50                    50                    50              150

And now we can calculate the statistic:

\chi^2 = \frac{(11-11)^2}{11}+\frac{(13-11)^2}{11}+\frac{(9-11)^2}{11}+\frac{(32-29)^2}{29}+\frac{(28-29)^2}{29}+\frac{(27-29)^2}{29}+\frac{(7-10)^2}{10}+\frac{(9-10)^2}{10}+\frac{(14-10)^2}{10} =3.81

Now we can calculate the degrees of freedom for the statistic given by:

df=(rows-1)(cols-1)=(3-1)(3-1)=4

And we can calculate the p value given by:

p_v = P(\chi^2_{4,0.05} >3.81)=0.43233

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(3.81,4,TRUE)"

Since the p values is higher than the significance level we FAIL to reject the null hypothesis at 5% of significance, and we can conclude that we don't have significant differences between the 3 remedies analyzed.

4 0
3 years ago
Use an equation to find the value of k so that the line that passes through the given points has the given slope. (
shutvik [7]

The formula of a slope:

m=\dfrac{y_2-y_1}{x_2-x_1}

We have the points (4, -4) and (k, -1) and the slope m = 34.

Substitute:

\dfrac{-1-(-4)}{k-4}=34\\\\\dfrac{3}{k-4}=\dfrac{34}{1}\qquad|\text{cross multiply}\\\\34(k-4)=3\qquad|\text{use distributive property}\\\\34k-136=3\qquad|+136\\\\34k=139\qquad|:34\\\\k=\dfrac{139}{34}

3 0
3 years ago
A bag contains 5 red marbles, 8 blue marbles and 6 green marbles. If three marbles are drawn out of the bag, what is the probabi
Gala2k [10]

70000000000 + 8818282828828

8 0
2 years ago
Write 3 numbers less than 50 that have exactly 3 factors
tino4ka555 [31]

Answer:

10,20,40

Step-by-step explanation:

They all have a factor of 2,10, and 1

6 0
3 years ago
The number 8,046 can be modeled using base ten blocks. How many of each type of block are needed to build the number?
MArishka [77]

Answer:

the first one

Step-by-step explanation:

8 one thousand block is 8000

0 hundreds 000

4 tens. 40

6 ones. 6

8046

7 0
2 years ago
Read 2 more answers
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