Given: ∠ DEF
To construct: ∠TSZ ≅ ∠DEF
Construction: Consider the attachment
Step-01: Draw a line XY and choose a point S on it as a vertex of the required angle. Further marks point T such that DE = ST
Step-02: Take an arc AB from point E in ∠DEF of any length and draw at point S which cuts at point P on XY line.
Step-03: Take another arc of length AB from point B in ∠DEF and draw from point P which cuts to the previous arc at Q.
Step-04: Now, join the point SQ and extend up to Z such that EF = SZ
Hence, ∠ TSZ will be the required congruent constructed angle to∠DEF
I think it would be 28100% i might be wrong
Length of square side= 2 cm
Dilation factor= 7/3
Simplify 7/3= 2.33
Apply the dilation factor:
Length of side= 2.33 x 2 = 4.67 cm
As the length of the side of the square is increased in length, which means the dilated image is larger than the original image.
Answer: Larger than then original.
3x- 11 +59 = 90
3x + 48 = 90
3x +48-48 =90-48
3x = 42
3x/3 = 42/3
x= 14
<MNQ = 3x -11
<MNQ = 3(14)-11
<MNQ = 42-11
<MNQ = 31
Answer:
5
Step-by-step explanation:
We can subtract both sides of the equation by 3, getting 3 + p - 3 = 8 - 3.
Then we can evaluate, getting p = 8 - 3 = 5.
