Y^3=x and 3y=x^2 is nonlinear
the others are linear
To find the inverse of f(x), you solve for the independent variable, x, and then swap the variable labels. The reason for doing so is easily seen if one remembers what an inverse function really is. The inverse function will produce the opposite coordinate as the parent function. If f(x)=(x,y), f^-1(x)=(y,x), so the inverse function simply creates the inverse of all of the points that exist for f(x)...with that out of the way, let y=f(x), then:
y=1/(9x-2) (I am trying to decipher what you actually meant to type)
Multiply both sides by (9x-2)
y(9x-2)=1 divide both sides by y
9x-2=1/y add 2 to both sides
9x=1/y+2 which is equal to
9x=(1+2y)/y divide both sides by 9
x=(1+2y)/(9y) now switch labels...
y=(1+2x)/(9x)
f^-1(x)=(1+2x)/(9x)
Again, I am not sure that I understood what you meant to type for the equation... strictly as typed you actually have:
y=x/9-2 which can be written as:
y=(x-18)/9 multiply both sides by 9
9y=x-18 add 18 to both sides
9y+18=x then switch labels
y=9x+18
f^-1(x)=9x+18
The denominator must be made clear in this format by using () brackets, otherwise it is anyone's guess...
The 1st equation, is the only one. PROOF:
f(x) = x⁴ - 2x² + 36x -80
1) f(2) = 2⁴ - 2(2)² + 36(2) - 80 = 0, hence 2 is a zero value (or a root)
2) f(-4) = (-4)⁴ - 2(-4)² + 36(-4) - 80 = 0, hence - 4 is another root.
Since x= 2 and x= -4, f(x) is then divisible by (x-2)(x+4) or if you proceed to this multiplication you will find:
(x-2)(x+4) = x² + 2x -8, that means f(x) is divisible by (x<span>² + 2x -8)
IDivide </span> (x⁴ - 2x² + 36x -80) / (x<span>² + 2x -8) you will find:
</span>
(x⁴ - 2x² + 36x -80) / (x² + 2x -8) = x² -2x +10. Now let's find the zeros of
x² -2x +10; x' = [-b+√(b²-4ac)]/2a and x" = [-b-√(b<span>²-4ac)]/2a, after plugging in the corresponding values you will find that:
</span>x' = 1+3i and x" = 1 - 3i ==> x<span>² -2x +10 = (x-1+3i)(x-1-3i)
and at last f(x) = </span>x⁴ - 2x² + 36x -80 = (x-2)(x+4)(x-1+3i)(x-1-3i), with following zeros: -2 , -4 , 1-3i and 1+3i
Answer:
67,600
Step-by-step explanation:
For the first and last two characters, there are ten possible digits (0 through 9) for each character.
For the second through sixth character, there are 26 possible letters (A through Z) for each character.
The number of all possible license plate combinations "n" is given by the multiplication of each digits range of possible outcomes:
Since there are no restrictions for repeated characters, there are 456,976,000 different license plate numbers are possible.
1.61 rounded to the nearest ten is 10.
I hope you like this answer, and please Brainliest me! Please have a great life. :D
