No, because there is not enough information given to make a conclusion. Providing a percentage of 46% higher profit per acre doesn't mean statistical significance as it could be data-based only. There should be a given p value to make a conclusion about statistical significance.
First we need to write the null and alternate hypothesis for this case.
Let x be the average number of text message sent. Then
Null hypothesis: x = 100
Alternate hypothesis: x > 100
The p value is 0.0853
If p value > significance level, then the null hypothesis is not rejected. If p value < significance level, then the null hypothesis is rejected.
If significance level is 10%(0.10), the p value will be less than 0.10 and we reject the null hypothesis and CAN conclude that:
The mean number of text messages sent yesterday was greater than 100.
If significance level is 5%(0.05), the p value will be greater than 0.05 and we cannot reject the null hypothesis and CANNOT conclude that:
The mean number of text messages sent yesterday was greater than 100.
Answer:
The solution is 
Step-by-step explanation:
We need to write everything as a power of 3.
We know that:
So
And
This following property is also important:
To solve, the first step is putting everything with the variable x on one side and everything without the variable x on the other side
This means that:
When you distribute, its basically when you give out things, as in, distribution.
Hope this helps!!
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