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snow_tiger [21]
3 years ago
14

A group of students wanted to investigate the claim that the average number of text messages sent yesterday by

Mathematics
1 answer:
Likurg_2 [28]3 years ago
7 0
First we need to write the null and alternate hypothesis for this case.

Let x be the average number of text message sent. Then

Null hypothesis: x = 100
Alternate hypothesis: x > 100

The p value is 0.0853

If p value > significance level, then the null hypothesis is not rejected. If p value < significance level, then the null hypothesis is rejected.

If significance level is 10%(0.10), the p value will be less than 0.10 and we reject the null hypothesis and CAN conclude that:
The mean number of text messages sent yesterday was greater than 100.

If significance level is 5%(0.05), the p value will be greater than 0.05 and we cannot reject the null hypothesis and CANNOT conclude that:
The mean number of text messages sent yesterday was greater than 100.
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Abel planned for a garden to be 42 m long but found that it needs to be 24 m long to fit in his backyard. He found the change of
Tom [10]

Question:

Abel planned for a garden to be 42 m long but found that it needs to be 24 m long to fit in his backyard. He found the change of scale below.

\frac{42m}{7}/{\frac{24m}{7} = \frac{6}{4}

Which is Abel’s error?

Abel should have written the ratio as 24 metres/7 metres

Abel should have written the ratio as 24 metres/42 metres

Abel should have divided both numbers by 6.

Abel should have divided both numbers by 4.

Answer:

Abel should have divided both numbers by 6.

Step-by-step explanation:

Given

Measured Length of backyard = 42m

Actual Length of backyard = 24m

Measured Ratio: \frac{42m}{7}/{\frac{24m}{7} = \frac{6}{4}

Required

Error in calculation of measured ratio

From Abel's calculation:

It can be observed that He divided both numbers by 7

Though 42/7 = 6 but that's not so for 24/7

24/7≠4;

Instead 24/7 = 3.43 (Approximated)

To get the actual ration, he has to divide both numbers by the highest common factor

The common factors of 42 and 24 include 2,3,6 of which the highest is 6

Hence; HCF of 42 and 24 = 6

So, we can conclude that the error in his calculation is having not dividing both numbers by 6

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These numbers are 12 and 14.
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