Step-by-step explanation:
Recall that

Therefore,

so


Answer: $0.28
Step-by-step explanation: Pic is attached. Hope this helps. Sorry for the bad handwriting, I'm writing with a mouse.
Answer:
3
Step-by-step explanation:

And,
$ \sum (2i+1)= \sum (2i)+ \sum_{i=1} ^{4} (1) $
$=\sum_{i=1} ^{4}(2i) + 1+1+1+1 $
$=\boxed{\Big(\sum_{n=1} ^{4}(2n)\Big) +4}.... \text{Variable in Summation doesn't matter}$
Hence the difference is 3.
Answer:
Step-by-step explanation: