Find the equation, f(x) = a(x-h)2 + k, for a parabola that passes through the point (1,-7) and has (2,- 4) as its vertex. What i
s the standard form of the equation?
1 answer:
The coordinates of the vertex are (h,k) so we can write:-
f(x) = a(x -2)^2 - 4
now when f(x) = -7 x = 1 so:-
-7 = a(1-2)^2 - 4
-7 = a - 4
a = -3
so the vertex formula is
f(x) = -3(x - 2)^2 - 4
standard form:-
f(x) = -3(x^2 - 4x + 4) - 4
= -3x^2 + 12x - 16
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-4g is what I got if ur evaluating
If it’s something about slope I got -4
10 (1/2) = 5
hope this helps
Answer is A
if x+y=5
y= -x+5
2x + (-x+5) =-2
2x -x +5 = -2
x+5 = -2
x=-7
Answer:
tough question guy needed more points to answer
Step-by-step explanation:
<h2>MARK AS BRAINLIEST </h2>
