let's firstly convert the decimal to a fraction, namely a rational.
so we have one decimal, thus let's use 1 zero at the denominator and lose the dot on the numerator.

so then, what rationals are between -8/5 and +8/5? well, a huge amount hmmm let's pick two.
![\bf \boxed{-\cfrac{8}{5}}\rule[0.35em]{9.5em}{0.25pt}~~-\cfrac{3}{5}~~\rule[0.35em]{2em}{0.25pt}0\rule[0.35em]{10em}{0.25pt}~~\cfrac{6}{5}~~\rule[0.35em]{2.5em}{0.25pt}\boxed{\cfrac{8}{5}}](https://tex.z-dn.net/?f=%5Cbf%20%5Cboxed%7B-%5Ccfrac%7B8%7D%7B5%7D%7D%5Crule%5B0.35em%5D%7B9.5em%7D%7B0.25pt%7D~~-%5Ccfrac%7B3%7D%7B5%7D~~%5Crule%5B0.35em%5D%7B2em%7D%7B0.25pt%7D0%5Crule%5B0.35em%5D%7B10em%7D%7B0.25pt%7D~~%5Ccfrac%7B6%7D%7B5%7D~~%5Crule%5B0.35em%5D%7B2.5em%7D%7B0.25pt%7D%5Cboxed%7B%5Ccfrac%7B8%7D%7B5%7D%7D)
(0,0)
Y=mx+b
m= slope
b=y intercept
Answer: H
Step-by-step explanation:
So this is called a problem you would use PEMDAS or (please-excuse-my-dear-aunt-sally)
Parenthesis
Exponents
Multiply
Divide
Addition
Subtract
In this sens, since parenthesis are present you do them first so it would be H
t(f) = 27*f
g(t) = $0.04*27*f
without the value for f (the number of friends) that is the farthest this can be solved.