The given substance combusts following the reaction:
C2H2 + (5/2)O2 -> 2CO2 + H2O
Assume C2H2 is an ideal gas. At STP, 1 mol of an ideal gas
occupies 22.4 L. Given 100.50 mL of C2H2, this means that there is 4.4866 x
10^(-3) mol. Combusting 1 mol of C2H2 consumes (5/2) mol of O2, then combusting
the given amount of C2H2 consumes 0.01121 mol of O2. At STP, this amount of O2
occupies 251.25 mL.
Answer:
5.94
Explanation:
At equilibrium
⇒[CH3NH^+] = 0.130/2= 0.065 M
hence we can write that
x= concentration of H+ ions
⇒2×10^(-11)×0.065 = x^2
⇒x= 1.14×10^{-6}
therefore ph=log [H+]= log[ 1.14×10^{-6}]= 5.94
Answer:
The sum of the numbers of protons and neutrons in the nucleus is called the mass number and, expressed in amu, is approximately equal to the mass of the atom. An atom is neutral when it contains equal numbers of electrons and protons.
Explanation:
hope this helps :)
Conversion factors is a ratio expressed as fraction that equal 1.
Conversion factor is a number used to change one set of units to another by multiplying or dividing.
I don’t really get your question tho so that’s wht I’m guessing