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Alborosie
3 years ago
7

A bowling ball has a mass of 10.0kg. If a net force of 35N is applied to the ball, what’s the acceleration?

Chemistry
1 answer:
Paraphin [41]3 years ago
3 0

Answer:

Acceleration =  3.5 m.s⁻²

Explanation:

Definition:

The acceleration is rate of change of velocity of an object with respect to time.

Formula:

a = Δv/Δt

a = acceleration

Δv = change in velocity

Δt = change in time

Units:

The unit of acceleration is m.s⁻².

Acceleration can also be determine through following formula,

F = m × a

a = F/m

Given data:

Force = 35 N  (N = Kg. m.s⁻²)

Mass = 10.0 Kg

a = ?

Formula:

a = F/m

a = 35 Kg. m.s⁻²/ 10.0 Kg

a =  3.5 m.s⁻²

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Juliette [100K]

1. This can be due to the dissolving of the solid in liquid and form a solution.

Dissolving is a physical property because dissolving doesn't form new substances and the chemical composition of the solid is not changed.

The color building up over the time can be due to the rate of dissolving of the solid and amount of particles have been dissolved.

Example:

  • Dissolving of CuSO₄ solid in water.
  • This develops a blue color.

2. This can be due to the chemical reaction between the solid and liquid.

Chemical reaction is a chemical property because from reacting substances new substances can be formed which the chemical formula is different from initial substances.

The color building up over the time can be due to the rate of the reaction and the amount of reactants.

Example:

  • The reaction between calcium metal with water.
  • The color of Ca(OH)₂ is white color.
  • Reaction is

       Ca(s) + 2H₂O(l) → Ca(OH)₂(aq) + H₂(g)

5 0
3 years ago
Cars run on gasoline, where octane (C8H18) is the principle component. This combustion reaction is responsible for generating en
Bezzdna [24]

Answer:

  • 10.19 g CO₂
  • 4.69 g H₂O

Explanation:

The combustion reaction of Octane is:

  • C₈H₁₈ → 8CO₂ + 9H₂O

To calculate the mass of CO₂ and H₂O produced, we need to know the mass of octane combusted.

We calculate the mass of Octane from the given volume and density, using the following <em>conversion factors</em>:

  • 1 gallon = 3.785 L
  • 1 L = 1000 mL

Now we<u> convert 1.24 gallons to mL</u>:

  • 1.24 gallon * \frac{3.785L}{1gallon} *\frac{1000mL}{1L} = 4693.4 mL

We <u>calculate the mass of Octane</u>:

  • 4693.4 mL * 0.703 g/mL = 3.30 g Octane

Now we use the <em>stoichiometric ratios</em> and <em>molecular weights</em> to <u>calculate the mass of CO₂ and H₂O</u>:

  • CO₂ ⇒ 3.30 g Octane ÷ 114g/mol * \frac{8molCO_{2}}{1molOctane} * 44 g/mol =  10.19 g CO₂
  • H₂O ⇒ 3.30 g Octane ÷ 114g/mol * \frac{9molH_{2}O}{1molOctane} * 18 g/mol = 4.69 g H₂O

7 0
4 years ago
Which of the following is true about an abiotic resource?
aev [14]

Answer:

B. It is a nonliving resource.

Explanation:

The definition of abiotic is "nonliving," and examples of abiotic resources may include soil or water.

5 0
3 years ago
Type the correct answer in the box. Express your answer to three significant figures. Calcium nitrate reacts with sodium phospha
RoseWind [281]

6.07 grams is the theoretical yield of calcium phosphate (Ca₃(PO₄)₂).

<h3>How we calculate mass from moles?</h3>

Mass of any substance can be calculated by using moles as:

n = W/M, where

W = required mass

M= molar mass

Given chemical reaction is:

3Ca(NO₃)₂ + 2Na₃PO₄ → 6NaNO₃ + Ca₃(PO₄)₂

From the stoichiometry it is clear that:

3 moles of Ca(NO₃)₂ = produce 1 mole of Ca₃(PO₄)₂

Given mass of Ca(NO₃)₂ = 96.1g

Mole of Ca(NO₃)₂ = 96.1g/164g/mol = 0.5859moles

So, 0.5859 moles of Ca(NO₃)₂ = produce 0.5859×1/3 = 0.0196 moles of Ca₃(PO₄)₂

Required mass of Ca₃(PO₄)₂ will be calculated by using moles as:

W = 0.0196mole × 310g/mole = 6.07 grams

Hence, 6.07 grams is the theoretical yield of calcium phosphate.

To know more about moles, visit the below link:

brainly.com/question/15373263

7 0
2 years ago
Which of the following is the term for the heaviness on something's surface that exerts a force over an area? a. force b. pressu
Elan Coil [88]

Answer:

i think the answer is pressure

3 0
3 years ago
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