Question

A bag contains 8 red crayons, 14 purple crayons, 6 yellow crayons, and 4 Green crayons. A crayon is selected, NOT replaced, then another is selected. Find the probability of two reds.
P(two reds)

Answer 1

Step-by-step explanation:

8+14+6+4=32

$\frac{8}{32}$

1

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4

Answer 2

Answer:

A bag contains 8 red crayons, 14 purple crayons, 6 yellow crayons, and 4 Green crayons.

=> Number of red crayons: 8

=> Total number of crayons: N = 8 + 14 + 6 + 4 = 32

=> The probability of selecting 2 red ones sequentially (without replacement):

P = (8/32) x (7/31) = 0.06

Hope this helps!

:)