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3 years ago

Is 24/3 its simplest form.

Mathematics

2 answers:

Dmitry [639]3 years ago

8 0

Answer:

Step-by-step explanation:

you can further divide it into 24/3 to get 8

labwork [276]3 years ago

6 0

Answer:

24/3=8, no.

Explanation:

24/3

divide the fraction by 3

24/3 =8

3/3=1

8*1=8

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Miranda bought 8 books about animals, 3 books about outer space, and 4 books about trains. Each book cost $5. How much did Miran

Svetradugi [14.3K]

She spent $75

The best news of this problem is that the books all cost the same.

So 8 + 3 + 4 = 15 books total
15 x $5 = $75

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3 years ago

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the hardcover version of a book weighs 7 ounces while its paperback version weighs 5 ounces. Forty-five copies of the book weigh

Nuetrik [128]

Keywords:

<em>System of equations, variables, hardcover version, paperback version, books </em>

For this case we must construct a system of two equations with two variables. Let "h" be the number of hardcover version books, and let "p" be the number of paperback version books. If the hardcover version of a book weighs 7 ounces and the paperback version weighs 5 ounces, to reach a total of 249 ounces we have:

$7h + 5p = 249$ (1)

On the other hand, if there are Forty-five copies of the book then:

$h + p = 45$ (2)

If from (2) we clear the number of books paperback version we have:

$p = 45-h$

As each paperback version book weighs 5 ounces, to obtain the total weight of the paperback version books, represented by "x" in the table shown, we multiply $5 * p = 5 (45-h)$

So, $x = 5 (45-h)$

Answer:

$x = 5 (45-h)$

Option D

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3 years ago

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What are two ways the debt to GDP ratio can decrease?

kobusy [5.1K]

Think of debt to GDP as a fraction. Debt / GDP

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3 years ago

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How are these identical??

Karolina [17]

Cuz They Are Identical Duhhh

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3 years ago

2x² - 5x+1 has roots alpha and beta. Find alpha⁴+beta⁴ without solving the equation.

shepuryov [24]

Answer:

Step-by-step explanation:

$\alpha+\beta=\dfrac{5}{2} \\\\\alpha*\beta=\dfrac{1}{2} \\\\\alpha^2+\beta^2=\dfrac{21}{4} \ (see\ previous\ post)\\\\(\alpha+\beta)^4=\dfrac{625}{16} \\\\=\alpha^4+\beta^4+4*\alpha^3*\beta+6*\alpha^2*\beta^2+4*\alpha*\beta^3\\\\=\alpha^4+\beta^4+4*(\alpha*\beta)(\alpha^2+\beta^2)+6*\alpha^2*\beta^2\\\\\alpha^4+\beta^4=(\alpha+\beta)^4-4*(\alpha*\beta)(\alpha^2+\beta^2)-6*\alpha^2*\beta^2\\\\= \dfrac{625}{16} -4*\dfrac{1}{2} *\dfrac{21}{4} -6*(\dfrac{1}{2})^2 \\\\$

$= \dfrac{625}{16}- \dfrac{168}{16}-\dfrac{24}{16}\\\\\\= \dfrac{433}{16}$

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3 years ago