The distance of the road junction form Timpson is given as 21.57 miles.
<h3>We have to solve this using the Pythagoras theorem method</h3>We have AT =
√60² + 12² = 12√26
∠TMG = LN = 90 degrees
Therefore we have the system
When we cross multiply we would have to solve for TM
TM = 21.57 miles
Hence the distance of the road junction form Timpson is given as 21.57 miles.
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Answer:
Weight of Large Box = 18.5 kg
Weight of Large Box = 13.25 kg
Step-by-step explanation:
<u>Given:</u>
There are two types of boxes i.e. Large and Small
Let the weight of Large boxes = L kg
Let the weight of Small boxes = S kg
As per given statement:
Writing equation for above:
....... (1)
Writing equation for above:
Now, by solving the equations (1) and (2), we can get the values of L and S.
<em>Multiplying equation (2) with 2 and subtracting from equation (1):</em>
-
-
--------------------
L = 18.5 Kg
Putting value of L in equation (1):
So, the answer is:
Weight of Large Box = 18.5 kg
Weight of Large Box = 13.25 kg
