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Fynjy0 [20]
3 years ago
5

Which of the following circles have their centers in the second quadrant? Check all that apply.

Mathematics
1 answer:
erastova [34]3 years ago
6 0

Answer:

B and C

Explanation:

Coordinates of A: (5,-5), which is in the 4th quadrant.

Coordinates of B: (-12,9), which is in the 2nd quadrant.

Coordinates of C: (-3,2), which is in the 2nd quadrant.

Coordinates of D: (2,-7), which is  in the 4th quadrant.

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3 2/7 fraction that have the same value
zimovet [89]
46/14. Hoped this helped!
7 0
3 years ago
Find Sin A, Cos A, and Tan A given the following triangle.
Solnce55 [7]

Answer:

A

Step-by-step explanation:

sin A=(opposite side)/hypotenuse=a/c

cos A=(adjacent side)/hypotenuse=b/c

tan A=(opposite side)/(adjacent side)=a/b

8 0
2 years ago
The polynomial 3x ^ 3 - 16x ^ 2 + 31x - 20 the area of a trapezoidal desktop . Of the bases of the x ^ 3 - 5x the height of the
vaieri [72.5K]

Answer:

Step-by-step explanation:

Given:

Area = 3x^3 - 16x^2 + 31x - 20

Base:

x^3 - 5x

Area of trapezoid, S = 1/2 × (A + B) × h

Using long division,

(2 × (3x^3 - 16x^2 + 31x - 20))/x^3 - 5x

= (6x^3 - 32x^2 + 62x - 40))/x^3 - 5x = 6 - (32x^2 - 92x + 40)/x^3 - 5x = 2S/Bh - Ah/Bh

= 2S/Bh - A/B

= (2S/B × 1/h) - A/B

Since, x^3 - 5x = B

Comparing the above,

A = 32x^2 - 92x + 40

2S/B = 6

Therefore, h = 1

6 0
3 years ago
Simplify fully e x e x e x f/ e x e x f x f
mel-nik [20]

Given:

The given expression is

\dfrac{e\times e\times e\times f}{e\times e\times f\times f}

To find:

The simplified form of given expression.

Solution:

We have,

\dfrac{e\times e\times e\times f}{e\times e\times f\times f}

The common factors in numerator and denominator are e, e, f.

Cancel out the common factors.

=\dfrac{e}{f}

Therefore, the required expression is \dfrac{e}{f}.

6 0
2 years ago
Solve these equations for x.<br> 1. 12+6x = 5-2<br> 2. X-4 = {(6x – 54)<br> 3. – (3x – 12) = 9x – 4
Fynjy0 [20]
X for the equations are:

1.-1.5
2.10
3.1.333
8 0
3 years ago
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