3 years ago

Help pleaseeee I've been stuck on this

Mathematics

1 answer:

Luda [366]3 years ago

4 0

Check the picture below.

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Help please! y=2x+1 THATS THE PROBLEM the photos on linked

Mashutka [201]

Here is a picture of the graph put into desmos

Desmos is super easy all you have to do is put in the equation and it graphs it for you but you can also use it as a regular calculator.

8 0

3 years ago

Can someone help me with this ASAP??

Lena [83]

Answer:

3/5

Step-by-step explanation:

because bc is 2/5 away from each other while bd is 5/5 away from each other. 5/5 - 2/5 = 3/5

8 0

3 years ago

Read 2 more answers

1.5x - 1.9y = - 29 , x - 0.9 = 4.5

Katyanochek1 [597]

X-0.9 = 4.5
+0.9 +0.9
x = 5.4
( to get rid of the -0.9 beside the x, u have to do the opposite operation on both sides. if its -0.9, u have to add 0.9 on both sides)

not sure about the first one.

3 0

3 years ago

A student has some $5 bills and $10 bills in her wallet for a total of $100. The amount of $10 bills she has is 3 more than 3 ti

Sergeu [11.5K]

Answer:

she has 6 $5 bills and 4 $10 bills I think I'm not sure

7 0

3 years ago

Determine the radius of convergence of the following power series. Then test the endpoints to determine the interval of converge

tresset_1 [31]

Answer:

Radius of the convergence is R = $\frac{1}{21}$

and,

The Interval of convergence is $-\frac{1}{21}$

Step-by-step explanation:

Given function : Σ(21x)^k

Now,

Using the ratio test, we have

R = $\lim_{n \to \infty} |\frac{21x^{k+1}}{21x^{k}}|$

R = $\lim_{n \to \infty} |\frac{21x^{k}\times21x^{1}}{21x^{k}}|$

R = $\lim_{n \to \infty} |21x^{1}|$

now,

for convergence R|x| < 1

Therefore,

$\lim_{n \to \infty} |21x^{1}|$ < 1

$-\frac{1}{21}$

and,

Radius of the convergence is R = $\frac{1}{21}$

and,

The Interval of convergence is $-\frac{1}{21}$

8 0

3 years ago