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gtnhenbr [62]
3 years ago
15

I was told that if I had perfect attendance, I would get an extra 4% in my check as a bonus. Therefore, if I earned $960.00 befo

re any bonus, then my total income with perfect attendance would be __________."
Mathematics
1 answer:
MakcuM [25]3 years ago
3 0

Answer:

Your total income with perfect attendance would be $998.40

Step-by-step explanation:

First you need to figure out how much the 4% bonus is by multiplying 4% by $960.

But first you need to convert 4% to a decimal so it becomes 0.04

Then multiply it by $960 which would get you $38.40

So the 4% bonus is $38.40 but you need to know how much your total income is with the bonus.

So you need to add $38.40 and $960 which will get you $998.40

The total income with perfect attendance would be $998.40

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Answer:

  see attached

Step-by-step explanation:

A graphing calculator is useful for this.

The region of interest is below the parabola and above the line.

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3 years ago
How does an estimate help you place the decimal point when multiplying 3.9 ✖️5.3
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Answer: 20.67
Hope it helps
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3 years ago
What are the solutions of x^2+2x-3=0?
Nikolay [14]
X= 1,-3   If you factor equation you get x-1=0 and x+3=0

4 0
3 years ago
85×250=_______ + 387= _______
Neko [114]

Answer:

21,637

Step-by-step explanation:

You can just use a caculator- Or simple multiplication by putting it on top of eachother.

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Hope I helped!!

7 0
2 years ago
Read 2 more answers
Suppose that you take 120 mg of an antibiotic every 4 hr. The​ half-life of the drug is 4 hr​ (the time it takes for half of the
vodomira [7]

Answer:

The steady state amount of antibiotic in the bloodstream when t --> ∞ is 240 mg.

Step-by-step explanation:

Let the amount of antibiotic in one's bloodstream be given as Aₙ (where n = the number of half lives since the start of usage)

Let's follow the time line of events.

At t = 0 hr, the drug is taken

A₀ = 120 mg

At t = 4 hrs, n = 1, the drug is taken again

A₁ = (0.5×A₀) + 120

A₁ = (0.5×120) + 120 = 180 mg

At t = 8 hrs, n = 2, the drug is taken again,

A₂ = (0.5×A₁) + 120

A₂ = (0.5×180) + 120 = 210 mg

At t = 12 hrs, n = 3, the drug is taken again

A₃ = (0.5×A₂) + 120

A₃ = (0.5×210) + 120 = 225 mg

At this point, it becomes evident that at t = 4n hrs, n = n i.e. n half lives later, the general formula for the amount of the antibiotic in the bloodstream is

Aₙ = 0.5Aₙ₋₁ + 120

where Aₙ₋₁ = The amount of antibiotic in the bloodstream at the time t = 4(n-1) and (n-1) half lives later.

For infinite series, that are increasing in this order, as the value of n --> ∞,

Aₙ = Aₙ₋₁ = K

And our general formula becomes

K = 0.5K + 120

0.5K = 120

K = (120/0.5)

K = 240 mg

Hence, the steady state amount of antibiotic in the bloodstream when t --> ∞ is 240 mg.

Hope this Helps!!!

5 0
3 years ago
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