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emmainna [20.7K]
4 years ago
15

How many switches does the diagram show? A)one B)two c)three d)four

Physics
2 answers:
ruslelena [56]4 years ago
6 0
The diagram shows two switches, both closed.
scoray [572]4 years ago
4 0
B) two is the answer
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During energy conversions, some energy is always lost as _____. light , heat , electricity or chemical energy?
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A bicyclist starting from rest applies a force of F = 454 N to ride his bicycle across flat ground for a distance of d = 250 m b
frutty [35]

Answer:

1.) 113500J

2.) 237m

Explanation:

Hello!

To solve this exercise follow the following steps, the description and complete process is in the attached image

1. Draw the full sketch of the problem.

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3. The potential energy is equal to the product of mass, gravity and height and is equal to the work done by the force applied by the cyclist, of this relationship and using algebra we can find the height that the cyclist climbed

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DedPeter [7]

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7 0
3 years ago
The charge entering the positive terminal of an element is q = 5 sin 4πt mC while the voltage across the element (plus to minus)
Artemon [7]

Answer:

(a). The power delivered to the element is 187.68 mW

(b). The energy delivered to the element is 57.52 mJ.

Explanation:

Given that,

Charge q=5\sin4\pi t\ mC

Voltage v=3\cos4\pi t\ V

Time t = 0.3 sec

We need to calculate the current

Using formula of current

i(t)=\dfrac{dq}{dt}

Put the value of charge

i(t)=\dfrac{d}{dt}(5\sin4\pi t)

i(t)=5\times4\pi\cos4\pi t

i(t)=20\pi\cos4\pi t

(a).We need to calculate the power delivered to the element

Using formula of power

p(t)=v(t)\times i(t)

Put the value into the formula

p(t)=3\cos4\pi t\times20\pi\cos4\pi t

p(t)=60\pi\times10^{-3}\cos^2(4\pi t)

p(t)=60\pi\times10^{-3}(\dfrac{1+\cos8\pi t}{2})

Put the value of t

p(t)=60\pi\times10^{-3}(\dfrac{1+\cos8\pi\times0.3}{2})

p(t)=30\pi\times10^{-3}(1+\cos8\pi \times0.3)

p(t)=187.68\ mW

(b). We need to calculate the energy delivered to the element between 0 and 0.6 s

Using formula of energy

E(t)=\int_{0}^{t}{p(t)dt}

Put the value into the formula

E(t)=\int_{0}^{0.6}{30\pi\times10^{-3}(1+\cos8\pi \times t)}

E(t)=30\pi\times10^{-3}\int_{0}^{0.6}{1+\cos8\pi \times t}

E(t)=30\pi\times10^{-3}(t+\dfrac{\sin8\pi t}{8\pi})_{0}^{0.6}

E(t)=30\pi\times10^{-3}(0.6+\dfrac{\sin8\pi\times0.6}{8\pi}-0-0)

E(t)=57.52\ mJ

Hence, (a). The power delivered to the element is 187.68 mW

(b). The energy delivered to the element is 57.52 mJ.

6 0
3 years ago
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