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Charra [1.4K]
3 years ago
15

Which lists the evidense to varify a chemical change occurred instaed of a phicical change

Physics
2 answers:
mrs_skeptik [129]3 years ago
8 0
What are the options?
stich3 [128]3 years ago
4 0

Answer:

?do you have a picture of the options orr ?

Explanation:

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A particle with mass 1.81×10−3 kg and a charge of 1.22×10−8 C has, at a given instant, a velocity v⃗ =(3.00×104m/s)j^. What are
slava [35]

Answer:

The magnitude and direction of the acceleration of the particle is a= 0.3296\ \hat{k}\ m/s^2

Explanation:

Given that,

Mass m = 1.81\times10^{-3}\ kg

Velocity v = (3.00\times10^{4}\ m/s)j

Charge q = 1.22\times10^{-8}\ C

Magnetic field B= (1.63\hat{i}+0.980\hat{j})\ T

We need to calculate the acceleration of the particle

Formula of the acceleration is defined as

F = ma=q(v\times B)

a =\dfrac{q(v\times B)}{m}

We need to calculate the value of v\times B

v\times B=(3.00\times10^{4}\ m/s)j\times(1.63\hat{i}+0.980\hat{j})

v\times B=4.89\times10^{4}

Now, put the all values into the acceleration 's formula

a =\dfrac{1.22\times10^{-8}\times(-4.89\times10^{4}\hat{k})}{1.81\times10^{-3}}

a= -0.3296\ \hat{k}\ m/s^2

Negative sign shows the opposite direction.

Hence, The magnitude and direction of the acceleration of the particle is a= 0.3296\ \hat{k}\ m/s^2

7 0
3 years ago
Read 2 more answers
Two protons are released from rest, with only the electrostatic force acting. Which of the following statements must be true abo
ycow [4]

Answer:

(A)

Explanation:

We know , electric potential energy between two charge particles of charges "q" and "Q" respectively is given by kqQ/r where r is the distance between them.

Since the two charged particles are moving apart, the distance between them (r) increases and thus electrical potential energy decreases.

7 0
3 years ago
Weight=1500n area=0.5 m2 pressure=​
Dmitriy789 [7]

Answer: 6000N/m^2

Explanation:

Weight =1500N

Area =0.5m^2

Pressure =1500/(0.5^2)

               =6000N/m^2

Note: Newton is denoted by 'N' (Capital) and use '^' for powers.

8 0
3 years ago
What is the relationship between the acceleration of an object change in relation to its mass
yarga [219]

The relationship between mass and acceleration is an inverse proportionality

Explanation:

The relationship between the acceleration of an object and its mass is given by Newton's second law, which states that:

F=ma

where

F is the net force on the object

m is its mass

a is its acceleration

From the equation, we notice that if the force on the object is kept constant, then the mass and the acceleration are inversely proportional to each other. This means that:

  • If the mass of the object is increased, its acceleration will decrease
  • If the mass of the object is decreased, its acceleration will increase

Learn more about Newton's second law:

brainly.com/question/3820012

#LearnwithBrainly

3 0
3 years ago
The tub of a washer goes into its spin-dry cycle, starting from rest and reaching an angular speed of 5.0 rev/s in 8.0 s. At thi
alisha [4.7K]

Answer:

The total number of revolution is 50 rev.

Explanation:

Given that,

Angular speed = 5.0 rev/s

Time = 8.0 s

We need to calculate the angular acceleration

Using equation of angular motion

\omega_{f}-\omega_{i}=\alpha t

Put the value into the formula

5.0-0=\alpha\times8.0

\alpha=\dfrac{5.0}{8.0}

\alpha=0.625\ rev/s^2

We need to calculate the angular displacement

Using equation of angular motion

\theta=\omega_{i}t+\dfrac{1}{2}\alpha t^2

Put the value into the formula

\theta=0+\dfrac{1}{2}\times0.625\times(8.0)^2

\theta=20\ rev

Now, The washer coming to rest from top spin

We need to calculate the angular acceleration

Using equation of angular motion

\omega_{f}-\omega_{i}=\alpha t

\alpha=\dfrac{\omega_{f}-\omega_{i}}{t}

\alpha=\dfrac{0-5}{12}

\alpha=−0.4167\ rev/s^2

We need to calculate the angular displacement

Using formula of displacement

\theta'=\omega_{i}t+\dfrac{1}{2}\alpha t^2

Put the value into the formula

\theta'=5\times12+\dfrac{1}{2}\times(-0.4167)\times12^2

\theta'=30\ rev

We need to calculate the total number of revolution

\theta''=\theta+\theta'

\theta''=20+30

\theta''=50\ rev

Hence, The total number of revolution is 50 rev.

5 0
4 years ago
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