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Charra [1.4K]
3 years ago
15

Which lists the evidense to varify a chemical change occurred instaed of a phicical change

Physics
2 answers:
mrs_skeptik [129]3 years ago
8 0
What are the options?
stich3 [128]3 years ago
4 0

Answer:

?do you have a picture of the options orr ?

Explanation:

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5 points
AnnZ [28]

Answer:

a

Explanation:

jijjijuuuuhuhhhhhhhhhhhhh

7 0
3 years ago
g Warm water in a geothermal heating system enters the pipe of a radiator at 20 psia and 119oF with a flow rate of 235 cfm (ft3/
Vika [28.1K]

Answer:

See explanation

Explanation:

Notice that the condenser section includes both the hot water and space heater and station (3) is specified as being in the Quality region. Assume that 50°C is a reasonable maximum hot water temperature for home usage, thus at a high pressure of 1.6 MPa, the maximum power available for hot water heating will occur when the refrigerant at station (3) reaches the saturated liquid state. (Quick Quiz: justify this statement). Assume also that the refrigerant at station (4) reaches a subcooled liquid temperature of 20°C while heating the air.

Using the conditions shown on the diagram and assuming that station (3) is at the saturated liquid state

a) On the P-h diagram provided below carefully plot the five processes of the heat pump together with the following constant temperature lines: 50°C (hot water), 13°C (ground loop), and -10°C (outside air temperature)

b) Using the R134a property tables determine the enthalpies at all five stations and verify and indicate their values on the P-h diagram.

c) Determine the mass flow rate of the refrigerant R134a. [0.0127 kg/s]

d) Determine the power absorbed by the hot water heater [2.0 kW] and that absorbed by the space heater [0.72 kW].

e) Determine the time taken for 100 liters of water at an initial temperature of 20°C to reach the required hot water temperature of 50°C [105 minutes].

f) Determine the Coefficient of Performance of the hot water heater [COPHW = 4.0] (defined as the heat absorbed by the hot water divided by the work done on the compressor)

g) Determine the Coefficient of Performance of the heat pump [COPHP = 5.4] (defined as the total heat rejected by the refrigerant in the hot water and space heaters divided by the work done on the compressor)

h) What changes would be required of the system parameters if no geothermal water loop was used, and the evaporator was required to absorb its heat from the outside air at -10°C. Discuss the advantages of the geothermal heat pump system over other means of space and water heating

4 0
3 years ago
Convert 1 second into solar day.
otez555 [7]

DIVIDE 1 BY 86400 TO CONVERT 1 SECOND INTO SOLAR DAY.

6 0
3 years ago
A bike race against the clock takes place on a straight road. Yan drives at 37 km / h and he starts the course 30s before Christ
joja [24]

Given data:

Yan speed;

u_1=37\text{ km/h}

Christopher speed;

u_2=38.9\text{ km/h}

Christophe starts 30 s later than Yan. Therefore, Christophe takes 30 s less than Yan to reach the same distance.

Part (A)

The distance is given as,

d=ut

Let both Yan and Christophe meet at d distance from the start position. Therefore,

u_1t=u_2(t-30)

Substituting all known values,

\begin{gathered} (37\text{ km/h})t=(38.9\text{ km/h})\times(t-30) \\ \frac{(37\text{ km/h})}{(38.9\text{ km/h})}=\frac{(t-30)}{t} \\ 0.95=1-\frac{30}{t} \\ \frac{30}{t}=1-0.95 \\ \frac{30}{t}=0.05 \\ t=\frac{30}{0.05} \\ t=600\text{ s} \end{gathered}

Therefore, 600 s after Yan's departure Christophe will join him.

Part (B)

The distance is given as,

d=u_1t

Substituting all known values,

\begin{gathered} d=(37\text{ km/h})\times(600\text{ s}) \\ =(37\text{ km/h})\times(600\text{ s})\times(\frac{1\text{ hr}}{3600\text{ s}}) \\ \approx6.17\text{ km} \end{gathered}

Therefore, Christophe joins Yan after 6.17 km from the start.

3 0
1 year ago
Apollo 14 astronaut Alan B. Shepard Jr. used an improvised six-iron to strike two golf balls while on the Fra Mauro region of th
Illusion [34]

Complete Question

Apollo 14 astronaut Alan B. Shepard Jr. used an improvised six-iron to strike two golf balls while on the Fra Mauro region of the moon’s surface, making what some consider the longest golf drive in history. Assume one of the golf balls was struck with initial velocity v0 = 32.75 m/s at an angle θ = 32° above the horizontal. The gravitational acceleration on the moon’s surface is approximately 1/6 that on the earth’s surface. Use a Cartesian coordinate system with the origin at the ball's initial position.

Randomized Variables

vo 32.75 m/s

theta 32 degrees

What horizontal distance, R in meters, did this golf ball travel before returning to the lunar surface?

Answer:

The  horizontal distance is  R =  590.2 \ m  

Explanation:

From the question we are told that

 The initial  velocity is  v_o =  32.75 \  m/s

  The angle is  \theta =  26^o

  The gravitational acceleration of the moon is g_m  =  \frac{1}{6}  *  9.8   = 1.633 m/s^2

 Generally the distance traveled is mathematically represented as

    R =  \frac{v_o^2 sin 2(\theta)}{g_m}

=> R =  \frac{32.75^2 sin 2(32)}{1.633}

=> R =  590.2 \ m  

             

8 0
3 years ago
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