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Tpy6a [65]
3 years ago
14

Determine the number of bonding electrons and the number of nonbonding electrons in the structure of cs2.

Chemistry
2 answers:
Rus_ich [418]3 years ago
5 0

The number of bonding and non-bonding electrons in {\text{C}}{{\text{S}}_2} are \boxed8 and \boxed8 respectively.

Further explanation:

In order to determine the number of bonding and non-bonding electrons first, we need to draw the correct Lewis structure of {\text{C}}{{\text{S}}_2} the molecule.

The Lewis structure is the chemical representation of an element along with the nonbonding pairs. For covalent molecules, the number of electrons involved in bonding and the remaining nonbonding pairs can be represented while writing the Lewis structures. Lewis structures help predict the geometry, polarity, and reactivity of the molecules.

The central atom is usually the least electronegative atom other than hydrogen. Hence out of carbon and sulphur, the former will act as the central metal atom. So arrange the two sulphur atoms around the carbon. Next, determine the number of valence electrons.

The total number of valence electrons of {\text{C}}{{\text{S}}_2} is calculated as,

{\text{Total valence electrons}} = \left[ {\left( {\text{1}} \right)\left( {{\text{Valence electrons of Carbon}}} \right){t{ + }}\left( 2 \right)\left( {{\text{Valence electrons of sulphur}}} \right)} \right]  

Since carbon carries 4 valence electron and sulphur carries 6 valence electrons. So,

\begin{aligned}{\text{Total valence electrons}}\left( {{\text{TVE}}} \right) &= \left[ {\left( 1 \right)\left( 4 \right)+\left( 2\right)\left( 6 \right)}\right]\\&= 16\\\end{aligned}  

Lewis structure of {\mathbf{C}}{{\mathbf{S}}_{\mathbf{2}}} and its linear shape along with the bonding and non-bonding electron pairs is apparent in the attached image.

Out of 16 electrons, eight electrons are involved in the formation of four bonds between the carbon and two sulfur atom. Carbon forms one sigma and one pi bond with each sulfur atom respectively. So now we are left with 8 electrons. These will constitute the non-bonding (lone pairs). 2 lone are present on each sulfur atom.

Learn more:

1. Coordination number for lithium sulfide crystals: brainly.com/question/75586212

2. Scientific notation: brainly.com/question/4935921

Answer details:  

Grade: High School

Subject: Chemistry

Chapter: Molecular structure and chemical bonding.

Keywords: Lewis structure, valence electrons, CS2, a single bond, bonding electrons, non-bonding electrons, and total valence electrons.

trapecia [35]3 years ago
3 0
Carbon disulfide ( S=C=S)  is made up of one carbon atom and two sulfur atom. 
Carbon has 4 valence electrons while sulfur has 6 electrons. 
During bonding all the four carbon valence electrons are used in bonding while each sulfur atom contributes two electrons two the bond formation.
Therefore; 4 + 2(2) = 8 electrons are used for bonding, while 8 electrons ( four from each sulfur atom) are not used for bond formation. 
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Methane gas and chlorine gas react to form hydrogen chloride gas and carbon tetrachloride gas. What volume of hydrogen chloride
IrinaK [193]

The question is incomplete, here is the complete question:

Methane gas and chlorine gas react to form hydrogen chloride gas and carbon tetrachloride gas. What volume of hydrogen chloride would be produced by this reaction if 1.1 mL of methane were consumed? Be sure your answer has the correct number of significant digits.

<u>Answer:</u> The volume of hydrogen chloride produced in the reaction will be 4.4 mL

<u>Explanation:</u>

We are given:

Volume of methane gas = 1.1 mL

The chemical equation for the reaction of methane gas and chlorine gas follows:

CH_4(g)+4Cl_2(g)\rightarrow 4HCl(g)+CCl_4(g)

Moles of methane gas = 1 mole

Moles of hydrogen chloride gas = 4 moles

The relationship of number of moles and volume at constant temperature and pressure was given by Avogadro's law. This law states that volume is directly proportional to number of moles at constant temperature and pressure.

The equation used to calculate number of moles is given by:

\frac{V_1}{n_1}=\frac{V_2}{n_2}

where,

V_1\text{ and }n_1 are the volume and number of moles of methane gas

V_2\text{ and }n_2 are the volume and number of moles of hydrogen chloride

We are given:

V_1=1.1mL\\n_1=1mol\\V_2=?L\\n_2=4mol

Putting values in above equation, we get:

\frac{1.1}{1}=\frac{V_2}{4}\\\\V_2=\frac{1.1\times 4}{1}=4.4mL

Hence, the volume of hydrogen chloride produced in the reaction will be 4.4 mL

5 0
3 years ago
17. Write the molecular balanced equation for the recovering of copper metal. 18. Write the complete ionic balanced equation for
eimsori [14]

Answer:

Explanation:

17. it goes from solid copper to aqueous copper:

Cu(s) --> Cu₂(aq) + 2e⁻

18. complete ionic:

Cu(s) --> Cu₂(aq) + 2e⁻

19. net ionic, must include only reacting species, so

Cu(s) --> Cu₂(aq) + 2e⁻

20. this type of reaction is dissolution reaction(redox reaction)

copper reduced from Cu²⁺ to Cu.

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3 years ago
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Answer:

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7 0
2 years ago
Five kilograms of liquid carbon tetrachloride undergo a mechanically reversible, isobaric change of state at 1 bar during which
Drupady [299]

Answer:

Explanation:

From the information given:

Mass of carbon tetrachloride = 5 kg

Pressure = 1 bar

The given density for carbon tetrachloride = 1590 kg/m³

The specific heat of carbon tetrachloride =  0.84 kJ/kg K

From the composition, the initial volume of carbon tetrachloride will be:= \dfrac{5 \ kg }{1590 \ kg/m^3}

= 0.0031 m³

Suppose \beta is independent of temperature while pressure is constant;

Then:

The change in volume can be expressed as:

\int ^{V_2}_{V_1} \dfrac{dV}{V} =\int ^{T_2}_{T_1} \beta dT

In ( \dfrac{V_2}{V_1})  = \beta (T_2-T_1)

V_2 = V_1 \times exp (\beta (T_2-T_1))

V_2 = 0.0031 \ m^3  \times exp  (1.2 \times 10^{-3} \times 20)

V_2 = 0.003175 \ m^3

However; the workdone = -PdV

W = -1.01 \times 10^5 \ Pa \times ( 0.003175 m^3 - 0.0031 \ m^3)

W = - 7.6 J

The heat energy Q = Δ h

Q = mC_p(T_2-T_1)

Q = 5 kg \times 0.84 \ kJ/kg^0 C \times 20

Q = 84 kJ

The internal energy is calculated by using the 1st law of thermodynamics; which can be expressed as;

ΔU = ΔQ + W

ΔU = 84 kJ + ( -7.6 × 10⁻³ kJ)

ΔU = 83.992 kJ

3 0
3 years ago
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