Temperature deciduous forest
Answer: I just took the test, the answer is A.
Explanation:
Answer:
The relationship is expressed as follows: ![K_{a} = \frac{[H+][A-]}{[HA]}](https://tex.z-dn.net/?f=K_%7Ba%7D%20%3D%20%5Cfrac%7B%5BH%2B%5D%5BA-%5D%7D%7B%5BHA%5D%7D)
Explanation:
Most acidic substances are weak acids and are therefore only partially ionized in acqeous solution. We cab use the equilibrium constant for the ionization of acid to express the extent to which the weak acid ionizes. If we represent a general weak acid as HA, we can write the equation for its ionization reaction like this:
To calculate the pH of a weak acid, we use the equilibrium concentration of the reacted species and product.
Take for example:
HA → H + A⁻
where A id the conjugate base.
Knowing that x amount of acid reacts, we can solve like this:
HA → H + A⁻
H+ = antilog (pH)
thus, the pH of the acid is equals to H+ (initial) - H+ (equilibrium) ≈ H+ (initial)
Answer:
- <u>Decreasing the temperature of the system will shift the reaction rightward.</u>
Explanation:
The complete question is:
Given the equation representing a system at equilibrium:
- N₂(g) + 3H₂(g) ⇌ 2NH₃(g) + energy
what changes occur when the temperature of this system is decreased?
<h2>Solution</h2>
Modifying the temperature of a system in equilibrium changes the equilibrium constant and the equilibrium position (concentrations) of the system.
When the temperature is decreased, following LeChatelier's principle that the system will react in a way that seeks to counteract the disturbance, the reaction will shift toward the reaction that produces more heat energy to compensate the temperature decrease.
Thus, decreasing the temperature of the system will favor the forward reaction, more N₂(g) and H₂(g) will be consumed and more NH₃(g) and energy will be produced. Hence, the equilibrium will shift rightward.
