This problem is providing us with the chemical equation depicting the production of ammonia from nitrogen and hydrogen at equilibrium and asks for the correct change when the concentration of nitrogen is increased. At the end, the answer is the forward reaction would increase to start reducing the concentration of N2.
<h3>Chemical equilibrium</h3>
In chemistry, chemical reactions not always reach a 100-% conversion when reactants get in contact in order to carry out the chemical reaction. Thus, there is a point wherein the concentrations remain the same and is called equilibrium.
In such a way, for this problem, we have the following chemical reaction at equilibrium:

Now, according to the Le Ch.atelier's principle, an increase in the concentration of any species, shifts the equilibrium away from it, which means that if we increase the concentration of nitrogen, a reactant, the forward reaction will be favored.
Thereby, the correct answer is "the forward reaction would increase to start reducing the concentration of N2".
Learn more about chemical equilibrium: brainly.com/question/26453983
Answer:
20.2 kJ
Explanation:
Based on the information in the reaction, the amount of heat released per mole of Na₂O₂ (the molar enthalpy) is calculated as follows:
126 kJ / 2 mol = 63 kJ/mol Na₂O₂
The number of moles in 25.0g of Na₂O₂ must be calculated using the molecular weight of Na₂O₂ (77.978 g/mol):
(25.0 g)/(77.978 g/mol) = 0.32060 mol Na₂O₂
Thus, the heat released will be:
(63 kJ/mol)(0.32060 mol) = 20.2 kJ
Answer:
The molarity of the solution is 4M
Explanation:
Molarity is defined as the amount of moles of solute present in one liter of solution. So the molarity of any solution can be found by dividing the moles of solute between the volume in liters of the solution.
For this case we have:

<span>17 (VIA)... bromine is a liquid at STP
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