1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Mila [183]
3 years ago
11

Brainliest is given to the correct answer!

Mathematics
1 answer:
OlgaM077 [116]3 years ago
6 0

Answer:

a. p = 2\pi r + 8r

b. r = \frac{p}{2\pi + 8}

Step-by-step explanation:

a. Radius of semicircle (r) = r

Diameter of semicircle (d) = 2r

Length of rectangle (l) = 2*diameter of semicircle = 2*2r = 4r

Distance around the track (p) = circumference of circle + 2(l)

Note: the two semicircles of the track = 1 full circle

Circumference of full circle = πd = π*2r = 2πr

Distance around the track:

p = 2πr + 2(4r)

p = 2πr + 8r

b. Rewriting the formula to make radius, r, the subject of the formula in terms of distance around the track.

p = 2\pi r + 8r

Factor out r

p = r(2\pi + 8)

Divide both sides by (2π + 8)

\frac{p}{2\pi + 8} = \frac{r(2\pi + 8)}{2\pi + 8}

\frac{p}{2\pi + 8} = r

r = \frac{p}{2\pi + 8}

You might be interested in
I need a answer asap Please!!
Ganezh [65]

Answer:

The ordered pairs (3 , 6) , (5 , 10) show a proportional relationship ⇒ last answer

Step-by-step explanation:

* Lets explain how to sole the problem

- Proportional relationship describes a simple relation between

 two variables

- In direct proportion if one variable increases, then the other variable

 increases and if one variable decreases, then the other variable

 decreases

- In inverse proportion if one variable increases, then the other variable

 decreases and if one variable decreases, then the other variable

 increases

- The ratio between the two variables is always constant

- Ex: If x and y are in direct proportion, then x = ky, where k

 is constant

 If x and y in inverse proportion, then x = k/y, where k is constant

* Lets solve the problem

# Last table

∵ x = 3 and y = 6

∴ x/y = 3/6 = 1/2

∵ x = 5 and y = 10

∴ x/y = 5/10 = 1/2

∵ 1/2 is constant

∵ x/y = constant

∴ x and y are proportion

* The ordered pairs (3 , 6) , (5 , 10) show a proportional relationship

7 0
3 years ago
Please help! Solve x/12+1/3=−5/3. What is x?
Mama L [17]

the answer would be: x= -24

6 0
3 years ago
Read 2 more answers
What is the value of x
zheka24 [161]

Answer:

35

Step-by-step explanation: I used a protractor

3 0
3 years ago
Read 2 more answers
A textbook store sold a combined total of 290 math and history textbooks in a week. The number of math textbooks sold was 64 mor
11Alexandr11 [23.1K]

Answer:

113

Step-by-step explanation:

290 - 64 = 226

226 ÷ 2 = 113

4 0
2 years ago
State the name of the property illustrated below.
ivanzaharov [21]

Answer:

Step-by-step explanation:

This is the associative property for addition. In informal language, it says under addition, the order of the addition is not critical.

8 0
3 years ago
Other questions:
  • Quincy uses the quadratic formula to solve for the values of x in a quadratic equation. He finds the solution, in simplest radic
    6·2 answers
  • The average person blinks 1,000 time an hour. Using scientific notation, calculate the number of times the average person blinks
    15·2 answers
  • helpp meeeeeeeeee (08.06 MC)Consider the following dot plot. Of the following statements, which two characteristics of this dot
    10·2 answers
  • Write an equation for a line thst is perpendicular to the line given by x=5 and passes through 1,0
    7·1 answer
  • Which equation, in point-slope form, passes through (-2, 4) and has a slope of 3?
    6·1 answer
  • Help me please thanks
    5·2 answers
  • The perimeter of a square is 52 cm.<br> Calculate the area of the square
    7·2 answers
  • Someone please help meeeee
    12·2 answers
  • I do be needing help tho ngl
    14·2 answers
  • (sec^2 - 1) (cse^2 -1) Show work please
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!