Answer:
by multiplying any non-zero scalar number except 1 to given vector
Step-by-step explanation:
Scalar multiple of one vector is parallel to the vector.
So in given case, v1= (-3,2) and a vector, v2 parallel to it can be find by multiplying any non-zero scalar number except 1 to v1
i.e
v2= n*v1
n is any scalar non-zero number except 1
let n=2 (one of many possible options)
v2= 2*(-3,2)
=(-6,4) !
Cosine is the second one the first one is Sine and the last one is tangent
