Answer:
(a) 2 feet.
(b) 2 feet.
Step-by-step explanation:
We have been given that the velocity function
in feet per second, is given for a particle moving along a straight line.
(a) We are asked to find the displacement over the interval
.
Since velocity is derivative of position function , so to find the displacement (position shift) from the velocity function, we need to integrate the velocity function.




Using power rule, we will get:
![\left[\frac{t^{-\frac{1}{2}+1}}{-\frac{1}{2}+1}}\right] ^4_1](https://tex.z-dn.net/?f=%5Cleft%5B%5Cfrac%7Bt%5E%7B-%5Cfrac%7B1%7D%7B2%7D%2B1%7D%7D%7B-%5Cfrac%7B1%7D%7B2%7D%2B1%7D%7D%5Cright%5D%20%5E4_1)
![\left[\frac{t^{\frac{1}{2}}}{\frac{1}{2}}}\right] ^4_1](https://tex.z-dn.net/?f=%5Cleft%5B%5Cfrac%7Bt%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%7D%7B%5Cfrac%7B1%7D%7B2%7D%7D%7D%5Cright%5D%20%5E4_1)

Therefore, the total displacement on the interval
would be 2 feet.
(b). For distance we need to integrate the absolute value of the velocity function.


Since square root is not defined for negative numbers, so our integral would be
.
We already figured out that the value of
is 2 feet, therefore, the total distance over the interval
would be 2 feet.
First find out how much interest earned each month by multiplying .07 x 250.00 = 17.50.
Now Mr. Smith deposits 250.00 + 17.50(interest earned) = 267.50 per month
New monthly deposit is 267.50
(New monthly deposit) 267.50 x 39 (months) = 10,432.50
<span>Mr. Smith will have 10,432.50 in the account after 39 months. </span>
It’s c :) I did the test just trust me
Answer:
Their not supplementary but for sure so......
Answer:
see explanation
Step-by-step explanation:
Using the Sine rule in all 3 questions
(1)
=
, substitute values , firstly calculating ∠ B
[ ∠ B = 180° - (78 + 49)° = 180° - 127° = 53° ]
=
( cross- multiply )
a sin53° = 18 sin78° ( divide both sides by sin53° )
a =
≈ 22.0 ( to the nearest tenth )
(3)
=
, substitute values
=
( cross- multiply )
45 sinC = 35 sin134° ( divide both sides by 35 )
sinC =
, then
∠ C =
(
) ≈ 34.0° ( to the nearest tenth )
(5)
Calculate the measure of ∠ B
∠ B = 180° - (38 + 92)° = 180° - 130° = 50°
=
, substitute values
=
( cross- multiply )
BC sin50° = 10 sin38° ( divide both sides by sin50° )
BC =
≈ 8.0 ( to the nearest tenth )