Three consecutive numbers are x, x+1 and x+2.
Four times the first integer is 4x
The sum of the second and third is (x+1)+(x+2)=2x+3.
So, we have

Subtract 2x from both sides:

Divide both sides by 2:

So, you can't have three consecutive integers such that four times the first is 18 more than the sum of the other two: the three numbers would be 10.5, 11.5, 12.5.
In fact, you have

and

Answer:
1. deli, bakery, dairy;
2. deli, dairy, bakery;
3. bakery, dairy, deli;
4. bakery, deli, dairy;
5. dairy, bakery, deli;
6. dairy, deli, bakery
Step-by-step explanation:
6 possibilities
The numbered cubes might be referring the dice. We know that there are 36 ways of dice will occur.
Take the unique list of the following pair for which the sum is less than 6, and these are
(1,1) (1,2) (1,3) (1,4) (2,1) (2,2) (2,3) (3,1) (3,2) (4,1)
Therefore there are 10 possible ways we could get.
In probability, it is a ratio of the successful outcomes over the total number of possible outcomes.
P = 10/36 = 5/18
The answer would be X =90