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Pavel [41]
3 years ago
15

The fifth-grade classes at Brookfield School used five identical buses to go on a field trip. •There were a total of 40 seats on

each bus. •All of the seats on four buses were filled. •The fifth bus had 4/5 of the seats filled. •1/8 of all the passengers on the buses were adults. How many adults went on the field trip.
Mathematics
1 answer:
Eva8 [605]3 years ago
6 0
First things first, you need to figure out the amount of passengers on the fifth bus.

Solution:
40 x 4
--      -  = 32 passengers
 1  x 5
*The fifth bus has 32 people.
You can now figure out the total number of passengers in all of the buses.

(40 x 4) + 32 = 192
*Overall, all 5 buses have a total of 192 passengers.
Since you have the total number of passengers, you can now figure out the numbers of adults who went on the field trip, which is 1/8 of all the passengers.

Solution:
192 x 1
-----    - = 24 passengers
  1   x 8

The final answer is: 24 adults went on the field trip.
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If p q r is prime numbers such that pq+r=73, what is the least possible value of p+q+r
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The answer to this question would be: p+q+r = 2 + 17 + 39= 58

In this question, p q r is a prime number. Most of the prime number is an odd number. If p q r all odd number, it wouldn't be possible to get 73 since
odd x odd + odd= odd + odd = even
Since 73 is an odd number, it is clear that one of the p q r needs to be an even number. 

There is only one odd prime number which is 2. If you put 2 in the r the result would be:
pq+2= 73
pq= 71
There will be no solution for pq since 71 is prime number. That mean 2 must be either p or q. Let say that 2 is p, then the equation would be: 2q + r= 73

The least possible value of p+q+r would be achieved by founding the highest q since its coefficient is 2 times r. Maximum q would be 73/2= 36.5 so you can try backward from that. Since q= 31, q=29, q=23 and q=19 wouldn't result in a prime number r, the least result would be q=17
r= 73-2q
r= 73- 2(17)
r= 73-34=39

p+q+r = 2 + 17 + 39= 58
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