(i) The area of the cross section ABCDEFG is 1771.6cm³
(ii) The volume of the concrete lab is 212592 cm³
(iii) the total surface area of the concrete slab is 30284 cm²
(iv) The mass of the concrete slab is 40746.8 kg/m³.
Given, dimensions are 120 cm by 60 cm by
40 cm.
(i) area of cross section = 40 × 60 ₋ π(60 ₋10 ₋ 10)/2 . 1/2
= 1771.6 cm³
(ii) the volume of the concrete slab = 40 × 60 × 120 ₋ 1/2 π((60 ₋ 10 ₋10)/2)² . 120
= 212592 cm³
(iii) The total surface area is:
=40 × 120 × 2 ₊ 60 × 120 ₊ 1771.6 × 2 ₊ 10 × 120 × 2 ₊ 1/2 π(60 ₋ 10 ₋10) × 120
= 30284 cm²
(iv) Mass of the concrete slab given density is 2300 kg/m³
Mass = Volume × density
Mass = 17.716 m³ × 2300
= 40746.8 kg/m³
Hence we get the mass as 40746.8 kg/m³.
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the answer is C. because it is the only one that does not contain a common factor :)
Answer:
D(-5,3) and E(-5,1)
Step-by-step explanation:
|AB|² = (-1-5)² + (-6-2)²
|AB|² = 36 + 64
|AB|² = 100
|AB| = 10
AB/DE = 5
|DE| = 10/5 = 2
D(-5,3) and E(-5,1)
|DE|² = (-5+5)² + (3-1)²
|DE|² = 4
|DE| = 2
Verified
I think the answer is c. please tell me if i am right
9 1/2 = 19/2
(29/5) / (19/2)
When changing division to multiplication, flip the number (right hand side).
(29/5) * (2/19)
58/95
