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ladessa [460]
4 years ago
11

ADV GEOM S1 See pic

Mathematics
1 answer:
SOVA2 [1]4 years ago
8 0
I don't see the picture man

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All real cube roots of 100/27
Nadya [2.5K]

4.64158883

−2.32079442+4.01973384i

−2.32079442−4.01973384i

100 is not a perfect cube so it will never have a whole root

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5 0
3 years ago
Someone please help
shepuryov [24]

Answer:

A

Step-by-step explanation:

2 cubes horizontal,  3 cubes (down) vertical,  2 cubes horizontal.

4 0
3 years ago
1.why.do.we.need.election<br>​
Irina-Kira [14]
To vote for a well suited president to help run for the United States
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3 years ago
Read 2 more answers
Find the perimeter of the following shape (show all work and box your final answer):
Paraphin [41]
<h3>Answer:   11x + 6y + 11</h3>

=========================================

Work Shown:

To find the perimeter, we add up all the exterior side lengths.

P = perimeter

P = (side1) + (side2) + (side 3)

P = (2y-3x-3) + (12+5x+7y) + (9x-3y+2)

P = (-3x+5x+9x) + (2y+7y-3y) + (-3+12+2)

P = 11x + 6y + 11

5 0
3 years ago
Pls help asap!! pic is shown
dsp73

The points (-5, 1), (-2, 4), (2, 4), and (-5, 1) gives the piecewise defined function as the second option;

g(x) = x + 6, when x < -2

g(x) = x², when -2 ≤ x < 2

g(x) = 6 - x, when x ≥ 2

<h3>How can the correct piecewise defined function be found?</h3>

Parts of the function are:

x < -2

Slope = (4-1)/(-2-(-5)) = 1

Equation is: g(x) - 4 = x - (-2)

g(x) - 4 = x + 2

g(x) = x + 2 + 4 = x + 6

  • g(x) = x + 6

In the region, -2 ≤ x < 2, points on the graph are;

(-2, 4), (0, 0), (2, 4)

The above points corresponds with the function;

  • g(x) = x²

In the region x ≥ 2, we have;

Slope = -1

Equation is: g(x) - 4 = -1×(x - 2) = 2 - x

Therefore;

g(x) = 4+2 - x = 6 - x

  • g(x) = 6 - x

The rule for the piecewise defined function is therefore;

  • g(x) = x + 6, when x < -2
  • g(x) = x², when -2 ≤ x < 2
  • g(x) = 6 - x, when x ≥ 2

The correct option is therefore the second option;

Learn more about piecewise defined functions here:

brainly.com/question/11207865

#SPJ1

3 0
2 years ago
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