1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Serggg [28]
3 years ago
11

PLEASE HELP!!! Please help me answer the questions that are circled, I really need help!

Mathematics
1 answer:
saul85 [17]3 years ago
8 0

Answer:

Here:

Step-by-step explanation:

23. f(x) = \sqrt{x} and g(x) = x^2-5x

24. f(x) = x^2 and g(x) = x^3+1

28. f(x) = e^x and g(x) = sinx

29. f(x) = cosx and g(x) = \sqrt{x}

Basically, you try to find a function contained inside a function if that makes sense. For example in question 23, g(x) itself is a function =  x^2-5x. Same with f(x) = \sqrt{x} . In this case, when we try to fo f(g(x)), we are basically replacing x in the f(x) function by the equation in g(x). Hope this makes sense.

You might be interested in
Is -7/9 rational or irrational?
RideAnS [48]

Answer:

It is a rational.

Step-by-step explanation:

Rational is any number that can be written in a form of <em>f</em><em>r</em><em>a</em><em>c</em><em>t</em><em>i</em><em>o</em><em>n</em>.

8 0
3 years ago
Read 2 more answers
Weird math question.
Aneli [31]

Answer:

It is 4/11

Step-by-step explanation:

Let x = 0.363636363636

Now as there are two digits repeating immediately after decimal point, we multiply above by 100 and get

100x = 36.363636363636

Now subtracting first equation from second we get

99x = 36

and hence

x = 36/ 99

= (9 × 4) / (9 × 11)

which then equals

= 4/11

6 0
3 years ago
you roll a blue number cube and a green number cube. find P ( a number less than 2 on the blue vube and odd number on the green
Kruka [31]

ON the blue cube there are 4 numbers greater than 2 and on the blue cube, 3 of the numbers are odd. As soon as BOTH outcomes have to happen (AND), you multiply the probabilities.

<span><span>4/6</span>×<span>3/6</span>=<span><span>1/3</span></span></span>

6 0
3 years ago
Read 2 more answers
16 inches to centimeters
asambeis [7]

Answer:

In centimeters, it would be 40.64 centimeters.

7 0
3 years ago
Read 2 more answers
Jenna found three solution to a linear equation she graphed them, but they don't lie in a straight line. What errors could jenna
steposvetlana [31]

Answer:

A system of linear equation could only have 1 solution. This is because the straight lines will only have to meet, cross, or intersect each other once.

A system of linear equation could only have 1 solution. This is because the straight lines will only have to meet, cross, or intersect each other once.

There are many different methods in arriving to the final answer. However, errors cannot be perfectly avoided. One of these errors to mistakenly identify equations as linear. It is important that we know that the equations we are dealing with are of exact or correct  characteristics.

Also, if she had used substitution method, she might have mistakenly taken the value of one variable for the other.

5 0
3 years ago
Other questions:
  • Line l passes through the points (1, 3) and (2, 5), and
    5·1 answer
  • Write 6.04 x 10^-3 as an ordinary number
    10·1 answer
  • Translate the image by (x+4, y - 6)
    8·1 answer
  • Need help on the answer
    11·2 answers
  • Solve for x 3/4×+5/4=4×​
    11·2 answers
  • What is the equation of the line in slope-intercept form?
    12·1 answer
  • What is the slope of the line that passes through the points (-9, -3)(−9,−3) and (1, -3) ?(1,−3)? Write your answer in simplest
    11·1 answer
  • What is the next term of the arithmetic sequence?<br> −7,−3,1,5,9,
    14·1 answer
  • Find the following limit without using a graphing calculator or making a table.
    15·1 answer
  • Charis invested $140. She earned a simple interest of 3% per year on the initial investment. If no money was added or removed fr
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!