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Orlov [11]
3 years ago
6

What is the slope-intercept form of 3x + 5y = -15?​

Mathematics
1 answer:
aev [14]3 years ago
5 0

3x+5y=1 in slope-intercept form is y=−35x+15 .

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Find the missing side length.<br> 9<br> 37°<br> 6
elena55 [62]

Answer:

7

Step-by-step explanation:

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3 years ago
Graph the equation to solve the system. y=2x+7 1/2y=x+7/2
vlabodo [156]

Given equation is y=2x+7 and \frac{1}{2}y=x+\frac{7}{2}

Let's simplify the 2nd equation \frac{1}{2}y=x+\frac{7}{2} before we can start graph so that calculation will be easy

\frac{1}{2}y=x+\frac{7}{2}

multiply both sides by 2 to cancel out fractions

2*\frac{1}{2}y=2*x+2*\frac{7}{2}

y=2x+7

which is exactly same as the first equatoin so graph of both will be exactly same and solution will be infinitely many solutions.

y=2x+7 has y-intercept 7 so first point will be (0,7). Slope is 2 so rise 2 unit up then 1 right and graph the new point.


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3 years ago
The answer . What is the equation and the answer ?
Ksenya-84 [330]
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4 0
3 years ago
Find the equation of the plane that is parallel to the vectors left angle 3 comma 0 comma 3 right angle and left angle 0 comma 1
Sholpan [36]

Answer:

x + 3y -z - 3 = 0      

Step-by-step explanation:

We have to find the equation of plane that is parallel to the vectors

\langle 3,0,3\rangle, \langle0,1,3\rangle

The plane also passes through the point (2,0,-1).

Hence, the equation of plane s given by:

\displaystyle\left[\begin{array}{ccc}x-2&y-0&z+1\\3&0&3\\0&1&3\end{array}\right]\\\\=(x-2)(0-3) - (y-0)(9-0) + (z+1)(3-0)\\=-3(x-2)-9y+3(z+1)\\\Rightarrow -3x + 6 - 9y + 3z + 3 = 0\\\Rightarrow 3x + 9y -3z -9 = 0\\\Rightarrow x + 3y -z - 3 = 0

It is the required equation of plane.

4 0
3 years ago
Watch help video
adelina 88 [10]

Answer:

m= 6/-5

Step-by-step explanation:

m= y2-y1/x2-x1

m= 6-(-6)/-18-(-8)

m= 12/-10

m= 6/-5

8 0
3 years ago
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