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Alik [6]
3 years ago
15

A pizza place sells pizzas for $7 each plus a $4 delivery charge per order. If Pat orders 3 pizzas to be delivered, what will be

his total cost ?
Mathematics
2 answers:
aliya0001 [1]3 years ago
8 0
Thirty three will be his total cost
Ainat [17]3 years ago
7 0
7x3=21+4=$25 total of the order 
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consider quadrilateral ABCD as graphed above. rotate ABCD 90° clockwise about the origin, then dilate with a scale factor of 3/2
saw5 [17]

Answer:

A”=three possible answers (10.5) (21/2) or (10 1/2)

B”=9

C”=3

D”=(4.5) (9/2) or (4 1/2)

Step-by-step explanation: just cause

5 0
3 years ago
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The probability of winning the game is 7/10. What is the probability that they will lose?
cestrela7 [59]
3/10 is the probability of them losing.
8 0
3 years ago
Solve the equation 4(x – 2) = 3x + 1. Question 15 options: A) 3 B) 8 C) 9 D) 2
telo118 [61]

Answer:

x = 9

Step-by-step explanation:

Step 1: Write equation

4(x - 2) = 3x + 1

Step 2: Solve for <em>x</em>

  1. <u>Distribute 4:</u> 4x - 8 = 3x + 1
  2. <u>Subtract 3x on both sides:</u> x - 8 = 1
  3. <u>Add 8 to both sides:</u> x = 9

Step 3: Check

<em>Plug in x to verify it's a solution.</em>

  1. <u>Substitute:</u> 4(9 - 2) = 3(9) + 1
  2. <u>Parenthesis (add):</u> 4(7) = 3(9) + 1
  3. <u>Multiply:</u> 28 = 27 + 1
  4. <u>Add:</u> 28 = 28
5 0
3 years ago
What is the arithmetic rule to the sequence: <br>1/3,4/3,7/3<br><br>find: f(10)
makkiz [27]

The the value of f(n)=\frac{28}{3}

Step-by-step explanation:

The Arithemetic sequence is given as a,a+d,a+2d......a(n-1)d

and f(n)=a(n-1)d

The given sequence is 1/3,4/3,7/3...

By comapring with Arithemetic sequence,

we get a=1/3

a+d=4/3

1/3 + d = 4/3

d=1

To find value of f(10):

take n=10

f(n)=\frac{1}{3} +(10-1)1

f(n)=\frac{1}{3} +(9)1

f(n)=\frac{1+27}{3}

f(n)=\frac{28}{3}

8 0
3 years ago
2/3 n = p 8 - 3 what does p equal?
Karolina [17]

Answer:

Isolate the variable by dividing each side by factors that don't contain the variable.

p

=

n

12

+

3

8

Step-by-step explanation:

6 0
2 years ago
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