Answer:
The concentration of an anthracene solution is ![c = 3.560 *10^{-5}M](https://tex.z-dn.net/?f=c%20%3D%203.560%20%2A10%5E%7B-5%7DM)
Explanation:
From the question we are told that
The incident beam
is ![=1532](https://tex.z-dn.net/?f=%3D1532)
The fluorescence intensity is ![I = 775](https://tex.z-dn.net/?f=I%20%3D%20775)
The length of the medium is b = 0.875 cm
The molar extinction coefficient is ![\epsilon = 9.5 *10^3 M^{-1} cm^{-1}](https://tex.z-dn.net/?f=%5Cepsilon%20%3D%209.5%20%2A10%5E3%20M%5E%7B-1%7D%20cm%5E%7B-1%7D)
The proportionality constant k = 0.30
According to Lambert law the Absorbance of the anthracene solution is mathematically represented as
![A = log (I_O/I)](https://tex.z-dn.net/?f=A%20%3D%20log%20%28I_O%2FI%29)
Where ![I_o =P_o](https://tex.z-dn.net/?f=I_o%20%3DP_o)
and A is the Absorbance
Substituting value
![A = log( (1532)/(775))](https://tex.z-dn.net/?f=A%20%3D%20log%28%20%281532%29%2F%28775%29%29)
![=0.2960](https://tex.z-dn.net/?f=%3D0.2960)
Generally beers law can be represented mathematically as
![A = \epsilon c l](https://tex.z-dn.net/?f=A%20%3D%20%5Cepsilon%20c%20l)
where c is the concentration of an anthracene solution
Making c the subject of the formula
![c = \frac{A}{cl}](https://tex.z-dn.net/?f=c%20%3D%20%5Cfrac%7BA%7D%7Bcl%7D)
Substituting 0.875 cm for length = b ,
We have
![c = \frac{0.2960}{9.5*10^{3} * 0.875}](https://tex.z-dn.net/?f=c%20%3D%20%5Cfrac%7B0.2960%7D%7B9.5%2A10%5E%7B3%7D%20%2A%200.875%7D)
![c = 3.560 *10^{-5}M](https://tex.z-dn.net/?f=c%20%3D%203.560%20%2A10%5E%7B-5%7DM)
Its either 1 or 3,
NH3 is polar like HCl, which has hydrogen bonding...
I believe this is an acid hope this helps
Answer: since the sodium ion is Na+, and sulfate is SO4(2-), you'll need 2 sodiums for a sulfate, making sodium sulfate Na2SO4.
Explanation: