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Monica [59]
4 years ago
13

Calculate the concentration of an anthracene solution which produced a fluorescence intensity ( I ) of 775 when the irradiance o

f the beam incident to the sample ( P 0 ) was 1532 and the length of the medium ( b ) was 0.875 cm. Anthracene has a molar extinction coefficient ( ϵ ) of 9.5 × 10 3 M − 1 ⋅ cm − 1 . The proportionality constant k ′ for anthracene is 0.30.
Chemistry
1 answer:
Kay [80]4 years ago
6 0

Answer:

The concentration of an anthracene solution is  c = 3.560 *10^{-5}M

Explanation:

From the question we are told that

       The incident beam P_o is =1532

         The fluorescence intensity is  I = 775

          The length of the medium is b = 0.875 cm

         The molar extinction coefficient is  \epsilon = 9.5 *10^3 M^{-1} cm^{-1}

          The proportionality  constant k = 0.30

 

According to Lambert law the Absorbance of the anthracene solution is mathematically represented as

              A = log (I_O/I)

Where I_o =P_o

and A  is the  Absorbance

    Substituting value

                A = log( (1532)/(775))

                  =0.2960

Generally beers law can be represented mathematically as

                   A = \epsilon c l

where c is the concentration of an anthracene solution

Making c the subject of the formula

          c = \frac{A}{cl}

Substituting  0.875 cm for length = b ,

We have  

            c = \frac{0.2960}{9.5*10^{3} * 0.875}

              c = 3.560 *10^{-5}M

             

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