I am 100% sure it is A. I did the test and it showed it was A.
Please leave a thanks.
Step-by-step explanation:
dP/dt = -0.4P
Separate the variables and integrate.
dP/P = -0.4 dt
ln|P| = -0.4t + C
P = Ce^(-0.4t)
Use initial condition to find C.
2 = C^(0)
C = 2
P = 2e^(-0.4t)
dQ/dt = -1
Integrate.
Q = -t + C
Use initial condition to find C.
3 = 0 + C
C = 3
Q = -t + 3
Set the two equal.
2e(-0.4t) = -t + 3
Use a calculator to find t.
t = 2.156
The populations have the same size after 2.156 hours.
Answer: the answer is 6x + 12y
Step-by-step explanation:
An hour and 15 minutes I believe which would be 1 and 1/4
