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gulaghasi [49]
3 years ago
8

Help me please... the picture is down below:)

Mathematics
1 answer:
iren [92.7K]3 years ago
3 0

Answer:

x=35

Step-by-step explanation:

x+110+35=180

x+145=180

x=180-145

x=35

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Michele bought 3.50 pounds of dried fruit for $11.55. Her friend buys 7.25 pounds of peanuts for $25.38. Which is less expensive
Kisachek [45]

Answer:

fruit cost less by the

Step-by-step explanation:

one pound of fruit cost 3.30 and peanuts cost 3.50 per pound

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calculate the scale factor of abc to def enter answer as a whole number or as a fraction into lowest terms
SVETLANKA909090 [29]

Answer:

Scale is 1/6

Step-by-step explanation:

Since all sides and angles are identical these are congruent triangles

3 ways to solve:

Scale Factor = DE / AB = 12/72 = 1/6

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Salsk061 [2.6K]

Answer:

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Step-by-step explanation:

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3 years ago
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What is the number of diagonals that intersect at a given vertex of a hexagon, heptagon, 30-gon and n-gon?
DENIUS [597]

Answer:

i. 9

ii. 14

iii. 405

iv. \frac{n(n-3)}{2}

Step-by-step explanation:

The number of diagonals in a polygon of n sides can be determined by:

\frac{n(n-3)}{2}

where n is the number of its sides.

i. For a hexagon which has 6 sides,

number of diagonals = \frac{6(6-3)}{2}

                                   = \frac{18}{2}

                                   = 9

The number of diagonals in a hexagon is 9.

ii. For a heptagon which has 7 sides,

number of diagonals = \frac{7(7-3)}{2}

                                   = \frac{28}{2}

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iii. For a 30-gon;

number of diagonals = \frac{30(30-3)}{2}

                                          = \frac{810}{2}

                                         = 405

The number of diagonals in a 30-gon is 405.

iv. For a n-gon,

number of diagonals = \frac{n(n-3)}{2}

The number of diagonals in a n-gon is \frac{n(n-3)}{2}

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3 years ago
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