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Zina [86]
3 years ago
15

How much is 4500 g at $8.80 a kg

Mathematics
1 answer:
GuDViN [60]3 years ago
8 0
The answer to this question is 39.6.
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How many solutions do these equations have y= 3x+4 y+6=3x
Nataly [62]

Answer:

Step-by-step explanation:

hello :

the system is :  y= 3x+4....(*)

                         y+6=3x....(**)

by (**) : y = 3x - 6

so : y= 3x+4

      y= 3x - 6

means :  3x+4 = 3x - 6

                     4= -6.......(false)

conclusion : no reals  solutions

5 0
3 years ago
3/5 + 3/7 = it a Fraction problem
Rudik [331]
<span>3/5 + 3/7 
Multiply the denominator until they have the same common denominator.
21/35 + 15/35
Add the numerators but NOT the denominators
Final Answer: 36/35 or 1 1/35</span>
5 0
3 years ago
Read 2 more answers
Multiply. <br> -3.9(-5.7)(3) <br> The product is:
scZoUnD [109]

Answer:

66.69

Step-by-step explanation:

You start off with -3.9 x -5.7 which gives you a positive, and that positive is 22.23, then you multiply that number by 3, and you get 66.69.

7 0
3 years ago
Read 2 more answers
From a piece of tin in the shape of a square 6 inches on a side, the largest possible circle is cut out. What is the ratio of th
wel

Answer:

\sf \dfrac{1}{4} \pi \quad or \quad \dfrac{7}{9}

Step-by-step explanation:

The <u>width</u> of a square is its <u>side length</u>.

The <u>width</u> of a circle is its <u>diameter</u>.

Therefore, the largest possible circle that can be cut out from a square is a circle whose <u>diameter</u> is <u>equal in length</u> to the <u>side length</u> of the square.

<u>Formulas</u>

\sf \textsf{Area of a square}=s^2 \quad \textsf{(where s is the side length)}

\sf \textsf{Area of a circle}=\pi r^2 \quad \textsf{(where r is the radius)}

\sf \textsf{Radius of a circle}=\dfrac{1}{2}d \quad \textsf{(where d is the diameter)}

If the diameter is equal to the side length of the square, then:
\implies \sf r=\dfrac{1}{2}s

Therefore:

\begin{aligned}\implies \sf Area\:of\:circle & = \sf \pi \left(\dfrac{s}{2}\right)^2\\& = \sf \pi \left(\dfrac{s^2}{4}\right)\\& = \sf \dfrac{1}{4}\pi s^2 \end{aligned}

So the ratio of the area of the circle to the original square is:

\begin{aligned}\textsf{area of circle} & :\textsf{area of square}\\\sf \dfrac{1}{4}\pi s^2 & : \sf s^2\\\sf \dfrac{1}{4}\pi & : 1\end{aligned}

Given:

  • side length (s) = 6 in
  • radius (r) = 6 ÷ 2 = 3 in

\implies \sf \textsf{Area of square}=6^2=36\:in^2

\implies \sf \textsf{Area of circle}=\pi \cdot 3^2=28\:in^2\:\:(nearest\:whole\:number)

Ratio of circle to square:

\implies \dfrac{28}{36}=\dfrac{7}{9}

5 0
2 years ago
A video game requires at least 4 points to advance. Each solved puzzle is worth two points. Each solved riddle is worth 1 point.
Gwar [14]

Answer:

The graph in the attached figure

Step-by-step explanation:

Let

x -----> the number of solved puzzles

y -----> the number of solved riddles

we know that

2x+y \geq 4

The solution of the inequality is the shaded area above the solid line 2x+y=4

The slope of the solid line is negative m=-2

The y-intercept of the solid line is the point (0,4)

The x-intercept of the solid line is the point (2,0)

therefore

The graph in the attached figure

3 0
3 years ago
Read 2 more answers
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