All categories

3 years ago

Please help me with this Evaluate. √121

Mathematics

2 answers:

e-lub [12.9K]3 years ago

8 0

Its eleven. Your welcome.

Anuta_ua [19.1K]3 years ago

4 0

ELEVEN IS THE ANSWER.
DEAL WITH IT

You might be interested in

ASAP! GIVING BRAINLIEST! Please read the question THEN answer CORRECTLY! NO guessing. Show your work OR give an explaination.

lianna [129]

Answer:

The answer is 3x^2-x-6. Hope it helps you ❤️

3 0

3 years ago

I’ll give brainliest if correct

Tems11 [23]

Answer:

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Can u plz help me idk the answer plzz help!!!!

Tju [1.3M]

You have to know what it is before you solve the problem

8 0

3 years ago

Q3: Identify the graph of the equation and write and equation of the translated or rotated graph in general form. (Picture Provi

natta225 [31]

Answer:

b. circle; $2(x')^2+2(y')^2-5x'-5\sqrt{3}y'-6 =0$

Step-by-step explanation:

The given conic has equation;

$x^2-5x+y^2=3$

We complete the square to obtain;

$(x-\frac{5}{2})^2+(y-0)^2=\frac{37}{4}$

This is a circle with center;

$(\frac{5}{2},0)$

This implies that;

$x=\frac{5}{2},y=0$

When the circle is rotated through an angle of $\theta=\frac{\pi}{3}$ ,

The new center is obtained using;

$x'=x\cos(\theta)+y\sin(\theta)$ and $y'=-x\sin(\theta)+y\cos(\theta)$

We plug in the given angle with x and y values to get;

$x'=(\frac{5}{2})\cos(\frac{\pi}{3})+(0)\sin(\frac{\pi}{3})$ and $y'=--(\frac{5}{2})\sin(\frac{\pi}{3})+(0)\cos(\frac{\pi}{3})$

This gives us;

$x'=\frac{5}{4} ,y'=\frac{5\sqrt{3} }{4}$

The equation of the rotated circle is;

$(x'-\frac{5}{4})^2+(y'-\frac{5\sqrt{3} }{4})^2=\frac{37}{4}$

Expand;

$(x')^2+(y')^2-\frac{5\sqrt{3} }{2}y'-\frac{5}{2}x'+\frac{25}{4} =\frac{37}{4}$

Multiply through by 4; to get

$4(x')^2+4(y')^2-10\sqrt{3}y'-10x'+25 =37$

Write in general form;

$4(x')^2+4(y')^2-10x'-10\sqrt{3}y'-12 =0$

Divide through by 2.

$2(x')^2+2(y')^2-5x'-5\sqrt{3}y'-6 =0$

8 0

3 years ago

Scott brought $23.25 to the art supply store. He bought a brush, a sketchbook, and a paint set. The brush was one fourth as much

fenix001 [56]

Answer:

Paint set cost = 10.5 , Sketch book cost = 7 , Brush cost = 1.75

Step-by-step explanation:

Let the cost of paint set be = p

Cost of sketchbook 's' = (2 / 3) p

Cost of brush 'b' = 1/4th of s = 1 / 4 [ (2 / 3) p ] = (1 / 6) p

Total expenditure = Money bought - Money left = 23.25 - 4 = 19.25

Total expenditure = Cost of (pen + of sketchbook + of brush) = p + s + b

= p + (2 / 3) p + (1 / 6) p = 19.25 → p + 2p / 3 + p / 6 = 19.25

( 6p + 4p + p ) / 6 = 19.25 → 11p / 6 = 19.25 → p = ( 19.25 x 6 ) / 11

p = 10.5 ; s = (2 / 3) p = 2 / 3 (10.5) = 7 ; b = (1 / 6) p = 10.5 / 6 = 1.75

8 0

3 years ago