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3 years ago

Dan bought 20 bunches of seedless green grapes for $48.00 . How many bunches can buy if she has $12.00?

Mathematics

1 answer:

hammer [34]3 years ago

3 0

Answer:

Step-by-step explanation:

$12(20b/$48)=5b

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What is the answer to this equation6+3/34+21/2=

malfutka [58]

Answer:

282/17

Step-by-step explanation:

6+3/34 =207/34

and 207/34+21/2=282/17

3 0

3 years ago

What should be the first step in solving 13 y − 14 = 42?

AveGali [126]

Answer:

The first step should be adding 14 to both sides of the equation.

Step-by-step explanation:

14 must be added on both sides of the equation to get 13y by itself. The ultimate goal is to get y by itself if we are solving for y.

Once 14 is added on both sides, you'll get:

13y = 56.

Then 13 would be divided from both sides.

y = 4.3

8 0

3 years ago

What is the slope of the function f(x) = 6x + 10 * 1 10 6 16 Other:

Rom4ik [11]

Answer:

Step-by-step explanation:

6 is the slope of the function

5 0

2 years ago

The altitude of a triangle is increasing at a rate of 1.5 1.5 centimeters/minute while the area of the triangle is increasing at

seraphim [82]

Answer:

The base reduces at 3.75cm/min

Step-by-step explanation:

Given

Let

$h \to altitude$

$b \to base$

$A \to Area$

So:

$\frac{dh}{dt} = 1.5cm/min$

$\frac{dA}{dt} = 1.5^2cm/min$

The area of a triangle is:

$A = \frac{1}{2}bh$

Calculate b when $A =88cm^2; h =8cm$

$A = \frac{1}{2}bh$

$88=\frac{1}{2} * b * 8$

$88 =b * 4$

Solve for b

$b = 88/4$

$b = 22$

We have:

$A = \frac{1}{2}bh$

Differentiate with respect to time

$\frac{dA}{dt} =\frac{1}{2}(h\frac{db}{dt} + b\frac{dh}{dt})$

Substitute the following values in the above equation

$\frac{dh}{dt} = 1.5cm/min$ $\frac{dA}{dt} = 1.5^2cm/min$ $b = 22$ $h = 8$

$1.5 = \frac{1}{2}(8 * \frac{db}{dt} + 22 * 1.5)$

Multiply both sides by 2

$3 = 8 * \frac{db}{dt} + 22 * 1.5$

$3 = 8 * \frac{db}{dt} + 33$

Collect like terms

$8 * \frac{db}{dt} = 3 -33$

$8 * \frac{db}{dt} = -30$

Divide both sides by 8

$\frac{db}{dt} = -\frac{30}{8}$

$\frac{db}{dt} = -3.75$

4 0

3 years ago

Triangle A'B'C' is a rotation of triangle ABC by 60 degrees using Q as the center.

deff fn [24]

9514 1404 393

Answer:

see below

Step-by-step explanation:

When a figure is rotated about a center point, the central angle formed by any point on the figure and the corresponding image point will be the rotation angle. Every image point is the same distance from the center of rotation that the pre-image point was. No lengths or angles are changed: rotation is a "rigid motion", so the rotated figure is congruent with the original.

-Angle AQA' is 60 degrees.

-Triangles ABC and A'B'C' are congruent.

-Angle ABC is congruent to angle A'B'C'. (this is one of the angles of the congruent triangles)

-Segment BC is congruent to segment B'C'

-Segment AQ is congruent to segment A'Q.

7 0

3 years ago