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3 years ago

What is the solution to this system of linear equations?

Mathematics

1 answer:

timurjin [86]3 years ago

7 0

B is the answer to your question

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Really need help Solve the system of equation Y=8x+11 Y=5x+29 X= Y=

KonstantinChe [14]

Answer:

(6,35)

Step-by-step explanation:

Set both equations equal to each other and solve for x

8x+11=5x+29, Subtract 5x from both sides

3x+11=29, Subtract 11 from both sides

3x=18 Divide by 3

x=6

Substitute x=6 back into either equation to solve for y

y=8(6)+11

y=48+11

y=59

3 0

3 years ago

The least common denominator of 3/2 and 2/3

amid [387]

6 is the least common denominator

6 0

3 years ago

253 - 17 X3 85 + 52 - 36

julia-pushkina [17]

Answer:

253-17*3 = 253-51 = 202

Step-by-step explanation:

85+52-36 = 147-36 = 111

4 0

3 years ago

Estimate the integral ∫6,0 x^2dx by the midpoint estimate, n = 6

Anettt [7]

Splitting up the interval [0, 6] into 6 subintervals means we have

$[0,1]\cup[1,2]\cup[2,3]\cup\cdots\cup[5,6]$

and the respective midpoints are $\dfrac12,\dfrac32,\dfrac52,\ldots,\dfrac{11}2$ . We can write these sequentially as ${x_i}^*=\dfrac{2i+1}2$ where $0\le i\le5$ .

So the integral is approximately

$\displaystyle\int_0^6x^2\,\mathrm dx\approx\sum_{i=0}^5({x_i}^*)^2\Delta x_i=\frac{6-0}6\sum_{i=0}^5({x_i}^*)^2=\sum_{i=0}^5\left(\frac{2i+1}2\right)^2$

Recall that

$\displaystyle\sum_{i=1}^ni^2=\frac{n(n+1)(2n+1)}6$
$\displaystyle\sum_{i=1}^ni=\frac{n(n+1)}2$
$\displaystyle\sum_{i=1}^n1=n$

so our sum becomes

$\displaystyle\sum_{i=0}^5\left(\frac{2i+1}2\right)^2=\sum_{i=0}^5\left(i^2+i+\frac14\right)$
$=\displaystyle\frac{5(6)(11)}6+\frac{5(6)}2+\frac54=\frac{143}2$

8 0

2 years ago

Kristen was asked to write each of the numbers in the expression 80,000 x 25 using exponents. Her response was (8 x 10 to the po

Gnom [1K]

Kriste respone is wrong

Solution:

Given that,

Kristen was asked to write each of the numbers in the expression 80,000 x 25 using exponents

Her response was (8 x 10 to the power of 3) x 5 to the power of 2

No, the response of Kristen is wrong

Let us first understand about exponents

An exponent refers to the number of times a number is multiplied by itself

Given expression is:

$80000 \times 25$

Here, 80000 has 4 zeros

Therefore, it can be raised as 10 power 4

$80000 = 8 \times 10^4$

Thus the expression becomes:

$80000 \times 25 = 8 \times 10^4 \times 25$

Also, 25 can be written as 5 power 2

$80000 \times 25 = 8 \times 10^4 \times 5^2$

Thus given expression is written as (8 x 10 to the power 4) x 5 power to the power 2

Thus Kristen respone is wrong, because he has raised 10 to power 3

6 0

3 years ago