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erastova [34]
3 years ago
9

Because of ocean acidification, it is expected that in 2050 the mass of CaCO3 deposited annually in coral reefs will be 20% less

than is deposited currently. Calculate how much less CaCO3 in Kg is expected to be deposited in 2050 than would be deposited if ocean water pH were to remain at its current value.
Chemistry
1 answer:
uysha [10]3 years ago
7 0

Question is incomplete (See complete question below).

Given that the current annual global increase in mass of CaCO3 in Coral reefs is 1.5*10^12 kg/year. Because of ocean acidification, it is expected that in 2050 the mass of CaCO3 deposited annually in coral reefs will be 20% less than is deposited currently. Calculate how much less CaCO3 in Kg is expected to be deposited in 2050 than would be deposited if ocean water pH were to remain at its current value.

Answer:

Expected deposited weight is 3 * 10^11 kg

Explanation:

Given

Weight = 1.5 * 10^12 kg/year

Percentage less = 20%

Provided that the pH of the ocean water were to remain at its current value, the expected weight of CaCO3 is calculated as follows;

% less * weight.

Substitute in the values;

20% * 1.5 * 10^12 kg

= 0.2 x 1.5 x 10^12 kg

= 3 * 10^11 kg

Hence, the expected deposited weight is 3 * 10^11 kg

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Rate = ?

Inserting the values into the equation, we have;

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How does the use of synthetic oil impact the natural resource from which they are derived?
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Answer:

The relative rates of diffusion for methane and oxygen is 1.4142.

Methane gas will be able to travel 1.4142 meter in the same conditions.

Explanation:

To calculate the rate of diffusion of gas, we use Graham's Law.

This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. Mathematically written as:

\text{Rate of diffusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}

We are given:

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By taking their ratio, we get:

\frac{d_{CH_4}}{d_{O_2}}=\sqrt{\frac{m'}{m}}

\frac{d_{CH_4}}{d_{O_2}}=\sqrt{\frac{32}{16}}=1.4142

The relative rates of diffusion for methane and oxygen is 1.4142.

If oxygen gas travels 1 meters in time t.

Rate of diffusion of oxygen =d_{O_2}=\frac{1 m}{t}

If methane gas travels travels in y meters in time t.

Rate of diffusion of methane=d_{CH_4}=\frac{y }{t}

\frac{d_{CH_4}}{d_{O_2}}=\frac{\frac{y }{t}}{\frac{1 m}{t}}=1.4142

y = 1.4142 m

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What type of energy is stored in the bonds of chemical compounds? chemical energy compound energy element energy kinetic energy.
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5 0
2 years ago
A pharmaceutical company wants to test the efficiency of its new drug production techniques so they run 3 shifts of production f
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The percentage yield of the  new production technique is 82.8%

<h3>What is the percentage yield?</h3>

Production is the procedure by which finished products are obtained form the raw materials. The production process involves the passing of raw materials through a certain procedure that involves the use of certain machines and equipment to give us the required products.

We are told in the question that there are three shifts;

Shift 1 produces 4562 grams

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Average production from the three shifts = 4562 grams + 5783 grams +  5247 grams/3 = 5197 grams

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Now the percentage yield = actual yield/ theoretical yield * 100/1

percentage yield = 5197 grams/7000 grams * 100/1

percentage yield = 82.8%

Learn more about percentage yield :brainly.com/question/27492865

#SPJ1

3 0
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