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3 years ago

Rank the solutions below in order of increasing acidity. (Drag and drop into the appropriate area)

Chemistry

1 answer:

Vladimir79 [104]3 years ago

7 0

Answer:

0.1 M NaOH, 3 M NH3, 0.01 M CH3COOH, 0.01 M H2SO4, 0.1 M HCl

Explanation:

Strong acids are more acids than weak acids. In the same way, strong bases are more basic than weak bases that are in the same concentration.

Then, the more concentrated acid or base will be more acidic or basic.

CH3COOH. Weak acid

NaOH. Strong base

H2SO4. Strong acid

NH3. Weak base.

HCl. Strong acid

The less acid (More basic):

Strong base, weak base, weak acid, diluted strong acid, undiluted strong acid

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To make a sarurated solution, 36 g of sodium chloride is dissolved in 100 g of water at 293 k . Find its concentration at this t

nexus9112 [7]

Answer:

The answer is " $26.47\%$ "

Explanation:

Sodium chloride solute mass $=36 \ g$

Solvent water mass $=100\ g$

Calculating the solution mass = Solute mass + solvent mass

$= 36\ g +100\ g\\\\ = 136\ g\\\\$

Calculating the percentage of concentration:

$= \frac{solute\ mass}{solvent\ mass} \times 100\\\\=\frac{36\ grm}{136\ grm} \times 100\\\\=0.2647 \times 100\\\\=26.47 \%$

3 0

3 years ago

Please help!!! I’ll give brainlist

Darina [25.2K]

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3 years ago

Use the Trapezoid Rule to approximate the value of the definite integral

bogdanovich [222]

Answer:

7.0625

Explanation:

The trapezoidal rule ( this is an approximation ) tells you that the average of the left and right endpoints should be as follows,

$\int _a^bf\left(x\right)dx\:\approx \frac{\Delta \:x}{2}\left(f\left(x_0\right)+2f\left(x_1\right)+...+2f\left(x_{n-1}\right)+f\left(x_n\right)\right)$

where $\Delta \:x\:=\:\frac{b-a}{n}$ ... at this point we can apply the Riemann Formula, in order to divide the interval 0 ≤ x ≤ 2 into n = 4 subintervals of length $\:\Delta x=\frac{1}{2}\:$ .

$x_0=0,\:x_1=\frac{1}{2},\:x_2=1,\:x_3=\frac{3}{2},\:x_4=2$ ,

$\frac{\Delta x}{2}=\frac{\frac{1}{2}}{2}=\frac{1}{4}$

= $\frac{1}{4}\left(f\left(x_0\right)+2f\left(x_1\right)+2f\left(x_2\right)+2f\left(x_3\right)+f\left(x_4\right)\right)$ - Let's calculate the sub intervals for each, substituting to receive our solution.

$f\left(x_0\right)= 0$ ( this is as 0⁴ is 0 )

$2f\left(x_1\right)= 1/8$ ( this is as $2\left(\frac{1}{2}\right)^4=1/8$ )

$2f\left(x_2\right)=2$ ( 2 $*$ 1⁴ is 2 )

$2f\left(x_3\right)= 81/8$ ( this is as $2\left(\frac{3}{2}\right)^4 = 81/8$ )

And finally $f\left(x_4\right) = 16$ , as 2⁴ is 16. Therefore, let us plug in our solutions for each into the primary expression, and solve,

$\frac{1}{4}\left(0+\frac{1}{8}+2+\frac{81}{8}+16\right)$ = 7.0625 - this is our solution. The correct answer is option c, and i hope this clarifies why.