Answer:
"0.60 g" is the appropriate solution.
Explanation:
The given values are:
Volume of base,
= 30 ml
Molarity of base,
= 0.05 m
Molar mass of acid,
= 400 g/mol
As we know,
⇒ ![Molarity=\frac{Number \ of \ moles \ of \ base}{Number \ of \ solution}](https://tex.z-dn.net/?f=Molarity%3D%5Cfrac%7BNumber%20%5C%20of%20%5C%20moles%20%5C%20of%20%5C%20base%7D%7BNumber%20%5C%20of%20%5C%20solution%7D)
On substituting the values, we get
⇒ ![0.05=\frac{Number \ of \ moles \ of \ base}{30\times 10^{-3}}](https://tex.z-dn.net/?f=0.05%3D%5Cfrac%7BNumber%20%5C%20of%20%5C%20moles%20%5C%20of%20%5C%20base%7D%7B30%5Ctimes%2010%5E%7B-3%7D%7D)
⇒ ![Number \ of \ moles \ of \ base=0.05\times 30\times 10^{-3}](https://tex.z-dn.net/?f=Number%20%5C%20of%20%5C%20moles%20%5C%20of%20%5C%20base%3D0.05%5Ctimes%2030%5Ctimes%2010%5E%7B-3%7D)
⇒
hence,
⇒ ![Moles \ of \ acid=\frac{Mass \ of \ acid}{Molar \ mass \ of \ acid}](https://tex.z-dn.net/?f=Moles%20%5C%20of%20%5C%20acid%3D%5Cfrac%7BMass%20%5C%20of%20%5C%20acid%7D%7BMolar%20%5C%20mass%20%5C%20of%20%5C%20acid%7D)
On substituting the values, we get
⇒ ![1.5\times 10^{-3}=\frac{Mass \ of \ acid}{400}](https://tex.z-dn.net/?f=1.5%5Ctimes%2010%5E%7B-3%7D%3D%5Cfrac%7BMass%20%5C%20of%20%5C%20acid%7D%7B400%7D)
⇒ ![Mass \ of \ acid=1.5\times 10^{-3}\times 400](https://tex.z-dn.net/?f=Mass%20%5C%20of%20%5C%20acid%3D1.5%5Ctimes%2010%5E%7B-3%7D%5Ctimes%20400)
⇒ ![=0.60 \ g](https://tex.z-dn.net/?f=%3D0.60%20%5C%20g)
Polair molecule, because the oxygen is slightly more negative than the two hydrogen atoms. Making water slightly negative. Due to the fact oxygen holds the to valence electrons more than the two hydrogen atoms do.
Answer:
molarity of acid =0.0132 M
Explanation:
We are considering that the unknown acid is monoprotic. Let the acid is HA.
The reaction between NaOH and acid will be:
![NaOH+HA--->NaA+H_{2}O](https://tex.z-dn.net/?f=NaOH%2BHA---%3ENaA%2BH_%7B2%7DO)
Thus one mole of acid will react with one mole of base.
The moles of base reacted = molarity of NaOH X volume of NaOH
The volume of NaOH used = Final burette reading - Initial reading
Volume of NaOH used = 22.50-0.55= 21.95 mL
Moles of NaOH = 0.1517X21.95=3.33 mmole
The moles of acid reacted = 3.33 mmole
The molarity of acid will be = ![\frac{mmole}{volumne(mL)}=\frac{0.33}{25}=0.0132M](https://tex.z-dn.net/?f=%5Cfrac%7Bmmole%7D%7Bvolumne%28mL%29%7D%3D%5Cfrac%7B0.33%7D%7B25%7D%3D0.0132M)
Answer:
Structural
Explanation:
Isomerism is the existence of two or more compounds with the same molecular formula but different molecular structures due to the difference in the arrangement of atoms or spatial orientation of atoms.
Isomers have the same molecular formula but differs in their structural arrangement.
In organic chemistry, Isomerism can orginate from different arrangement of atoms.
It can be carbon chain length known as chain isomerism. Here, the carbon length is changed and arranged in different ways.
We can also have position isomerism which entails the position of the functional group in the structure.
It can also be functional group isomerism which deals with the possible arrangement of the group on the chain.
The most common pH indicator used in Simmons Citrate Agar is Bromthymol Blue (BTB)
Simmons Citrate Agar is a selective and differential medium used for the detection and differentiation of Enterobacteriaceae (gram-negative bacteria).
The medium contains sodium citrate as the sole carbon source, which is used to differentiate organisms based on their ability to utilize citrate as a sole carbon source.
The medium also contains pH indicators that change color based on the pH of the medium. The most common pH indicator used in Simmons Citrate Agar is Bromthymol Blue (BTB).
BTB is a pH indicator that turns yellow in acidic conditions and blue in basic conditions. As the bacteria metabolize the citrate in the medium, they produce acids, which cause the medium to become acidic.
This change in pH is detected by the BTB, which changes color from blue to yellow. The yellow coloration of the medium is an indication that the organism is utilizing citrate as a sole carbon source.
To know more about agar, click below:
brainly.com/question/4634808
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